A 25.0 mL sample of 0.35 M lactic acid, HC3H5O3, is titrated with 0.070 M KOH....

A 25.0 mL sample of 0.35 M lactic acid, HC3H5O3, is titrated with 0.070 M KOH. Determine the pH of the solution at the equivalence point and at half-way to equivalence point. The Ka of lactic acid is 1.38x10^-4.

Expert Solution

queen_honey_blossom answered 1 year ago

Applications of Aqueous Equilibria: A 25.0 mL sample of 0.100 M lactic acid (HC3H5O3, Ka =...

Applications of Aqueous Equilibria: A 25.0 mL sample of 0.100 M lactic acid (HC3H5O3, Ka = 1.38 X 10^-4) is titrated with a 0.100 M barium hydroxide. Calculate the pH after the addition of 0.0 mL, 2.0 mL, 4.0 mL, 6.25 mL, 10.0 mL, 12.0 mL, 12.25 mL, 12.5 mL, 13.0 mL, 14.0 mL, and 15.0 mL of the Ba(OH)2

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A 25.0 mL sample of 0.30 M HCOOH is titrated with 0.20 M KOH. What is the pH of the solution after 25.0 mL of KOH has been added to the acid? Ka = 1.8x10^-4

A 25.0-mL solution of 0.100 M acetic acid is titrated with a 0.200 M KOH solution....

A 25.0-mL solution of 0.100 M acetic acid is titrated with a 0.200 M KOH solution. Calculate the pH after the following additions of the KOH solution: a) 0.0 mL b) 5.0 mL c) 10.0 mL d) 12.5 mL e) 15.0 mL

Calculate the pH of 25.0 mL of 0.110 M aqueous lactic acid being titrated with 0.150...

Calculate the pH of 25.0 mL of 0.110 M aqueous lactic acid being titrated with 0.150 M NaOH(aq) [See text for Ka value.] (a) initially (b) after the addition of 5.0 mL of base (c) after the addition of a 5.0 mL more of base, Vt=10.0mL (d) at the equivalence point (e) after the addition of 5.0 mL of base beyond the equivalence point (f) after the addition of 10.0 mL of base beyond the equivalence point (g) Pick a...

2) A 25.0 mL sample of 0.160 M KOH is titrated with 0.250 M HCl. Determine...

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A 25.0 mL sample of a 0.110 M solution of acetic acid is titrated with a 0.138 M solution of NaOH. Calculate the pH of the titration mixture after 10.0, 20.0, and 30.0 mL of base have been added. The Ka for acetic acid is 1.76x10^-5.

A 25.0 mL sample of 0.150 M hydrazoic acid (HN3) is titrated with a 0.150 M...

A 25.0 mL sample of 0.150 M hydrazoic acid (HN3) is titrated with a 0.150 M NaOH solution. Calculate the pH at equivalence and the pH after 26.0 mL of base is added. The Ka of hydrazoic acid is 1.9x10^-5.

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A 25.0 mL sample of 0.150 M hydrofluoric acid is titrated with a 0.150 M NaOH solution. What is the pH at the equivalence point? The Ka of hydrofluoric acid is 6.8 × 10-4.

A 25.0 mL sample of 0.100 M acetic acid is titrated with a 0.125 M NaOH...

A 25.0 mL sample of 0.100 M acetic acid is titrated with a 0.125 M NaOH solution. Calculate the pH of the mixture after 10, 20, and 30 ml of NaOH have been added (Ka=1.76*10^-5)

9. A buffer is made by mixing 85 mL of 0.13 M lactic acid (HC3H5O3) with...

9. A buffer is made by mixing 85 mL of 0.13 M lactic acid (HC3H5O3) with 95 mL of 0.15 M sodium lactate. a. Calculate the pH of the buffer. b. Calculate the pH after 3.0 mL of a 0.20 M HCl solution is added to the buffer. c. Calculate the pH after 3.0 mL of a 0.20 M NaOH solution is added to the buffer INSTEAD of the HCl solution. d. Calculate the pH of the buffer solution if...

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