A 25.0 mL sample of 0.150 M hydrofluoric acid is titrated with a 0.150 M NaOH...

A 25.0 mL sample of 0.150 M hydrofluoric acid is titrated with a 0.150 M NaOH solution. What is the pH at the equivalence point? The K_a of hydrofluoric acid is 6.8 × 10^-4.

Expert Solution

volume of base at equivalence point needed = 25.0 mL

total volume of the solution = 25 + 25 = 50 .0 mL

at equivalence point only salt remains its concentration = 25 x0.150 / 50

= 0.075 M

pKa = -log Ka

pKa = -log (6.8 x 10^-4)

pKa = 3.17

pH = 7 + 1/2 [pKa + log C]

pH = 7 + 1/2 [3.17 + log 0.075]

pH = 8.02

queen_honey_blossom answered 2 years ago

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