Question

In: Physics

A 244 g mass is hung on a spring. As a result the spring stretches 20.5...

A 244 g mass is hung on a spring. As a result the spring stretches 20.5 cm. If the object is then pulled an additional 3.0 cm downward and released, what is the period of the resulting oscillation?

Please show work :)

F=kx found k, then use 2pi(sqrtm/k)? convert centimeters to meters and grams to kg? I resulted T= 0.972 confirm please.

Solutions

Expert Solution

Mass m = 244 g = 0.244 kg

Streached length L = 20.5 cm = 0.205 m

In spring ,at equilibrium , weight of the mass = restoring force

       mg = kL

From this spring constant k = mg / L

                                        = (0.244 x9.8) / 0.205

                                         = 11.664 N/m

Period of oscillations T = 2[m/k]

                                   = 2(22/7) [0.244 /11.664]

                                   =2(22/7)(0.144)

                                   = 0.9087 s

genius_generous answered 4 days ago
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