In: Operations Management
José Martinez of El Paso has developed a polished stainless-steel tortilla machine that makes it a “showpiece” for display in Mexican restaurants. He needs to develop a 5-month aggregate plan. His forecast of capacity and demand follows:
Month 1 | Month 1 | Month 1 | Month 1 | Month 1 | |
Demand | 150 | 160 | 130 | 200 | 210 |
Capacity | |||||
Regular | 150 | 150 | 150 | 150 | 150 |
Overtime | 20 | 20 | 10 | 10 | 10 |
Additional information: Subcontracting: 100 units available over the 5-month period, Beginning inventory: 0 units
Costs:
Regular time cost per unit = $100
Overtime cost per unit = $125
Subcontract cost per unit = $135
Inventory holding cost per unit = $3
Assume that back-orders are not permitted.
a. Using the transportation method, what is the total cost of the optimal plan? [ Select ] ["$90,140", "$86,100", "$88,150", "$85,500"]
b. Does any regular time production go unused? [ Select ] ["cannot determine", "no", "yes"] If so/not, how much is used or not used? 50 units
c. What is the total cost of the plan if ending inventory required for the next planning period is: 20 units (include holding costs in the overall calculation)? [ Select ] ["$88,150", "$90,850", "$90,910", "$91,900"]
please answer all the questions with the right answer thanks
Already Solved:
Produce in \ Used in | M1 | M2 | M3 | M4 | M5 | Total | Capacity |
Beginning inventory | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
M1 reg time | 150 | 0 | 0 | 0 | 0 | 150 | 150 |
M1 overtime | 0 | 0 | 0 | 0 | 0 | 0 | 20 |
M1 subcontract | 0 | 0 | 0 | 0 | 0 | 0 | 999 |
M2 reg time | 0 | 150 | 0 | 0 | 0 | 150 | 150 |
M2 overtime | 0 | 10 | 10 | 0 | 0 | 20 | 20 |
M2 subcontract | 0 | 0 | 0 | 0 | 0 | 0 | 999 |
M3 reg time | 0 | 0 | 110 | 40 | 0 | 150 | 150 |
M3 overtime | 0 | 0 | 10 | 0 | 0 | 10 | 10 |
M3 subcontract | 0 | 0 | 0 | 0 | 0 | 0 | 999 |
M4 reg time | 0 | 0 | 0 | 150 | 0 | 150 | 150 |
M4 overtime | 0 | 0 | 0 | 10 | 0 | 10 | 10 |
M4 subcontract | 0 | 0 | 0 | 0 | 0 | 0 | 999 |
M5 reg time | 0 | 0 | 0 | 0 | 150 | 150 | 150 |
M5 overtime | 0 | 0 | 0 | 0 | 10 | 10 | 10 |
M5 subcontract | 0 | 0 | 0 | 0 | 50 | 50 | 999 |
Total | 150 | 160 | 130 | 200 | 210 | ||
Demand | 150 | 160 | 130 | 200 | 210 | ||
Total Cost | $88,150 |
(a)
Total cost = $88,150
(b)
As we can see in the 'Total' column, all of the regular time capacity is utilized
(c)
Slightly change the formulation and keep the same solver input:
Solution:
Produce in \ Used in | M1 | M2 | M3 | M4 | M5 | Total | Capacity |
Beginning inventory | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
M1 reg time | 150 | 0 | 0 | 0 | 0 | 150 | 150 |
M1 overtime | 0 | 0 | 0 | 0 | 0 | 0 | 20 |
M1 subcontract | 0 | 0 | 0 | 0 | 0 | 0 | 999 |
M2 reg time | 0 | 150 | 0 | 0 | 0 | 150 | 150 |
M2 overtime | 0 | 10 | 0 | 10 | 0 | 20 | 20 |
M2 subcontract | 0 | 0 | 0 | 0 | 0 | 0 | 999 |
M3 reg time | 0 | 0 | 120 | 30 | 0 | 150 | 150 |
M3 overtime | 0 | 0 | 10 | 0 | 0 | 10 | 10 |
M3 subcontract | 0 | 0 | 0 | 0 | 0 | 0 | 999 |
M4 reg time | 0 | 0 | 0 | 150 | 0 | 150 | 150 |
M4 overtime | 0 | 0 | 0 | 10 | 0 | 10 | 10 |
M4 subcontract | 0 | 0 | 0 | 0 | 0 | 0 | 999 |
M5 reg time | 0 | 0 | 0 | 0 | 150 | 150 | 150 |
M5 overtime | 0 | 0 | 0 | 0 | 10 | 10 | 10 |
M5 subcontract | 0 | 0 | 0 | 0 | 70 | 70 | 999 |
Total | 150 | 160 | 130 | 200 | 230 | ||
Demand | 150 | 160 | 130 | 200 | 230 | ||
Total Cost | $90,910 |
Total cost = $90,910