In: Chemistry
What is the pH of 0.65 M lactic acid? Construct and use an ICE table. Use appropriate assumptions and test those assumptions. If an assumption is false redo the problem without the false assumption.
Please use an ICE table if you don't mind..
CH3CH(OH)COOH ------------------------------> CH3CH(OH)COO^- + H^+
I 0.65 0 0
C -x +x +x
E 0.65-x +x +x
Ka = [CH3CH(OH)COO^-][H^+]/CH3CH(OH)COOH]
1.38*10^-4 = x*x/0.65-x
1.38*10^-4*(0.65-x) = x^2
x = 0.0094
[H^+] = x = 0.0094M
PH = -log[H^=]
= -log0.0094 = 2.0268