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1. When 15.0 mL of a 9.06×10-4M sodium phosphate solution is combined with 15.0 mL of...

1. When 15.0 mL of a 9.06×10-4M sodium phosphate solution is combined with 15.0 mL of a 4.38×10-4M chromium(III) nitrate solution does a precipitate form?  (yes or no)

For these conditions the Reaction Quotient, Q, is equal to

2. When 18.0 mL of a 5.83×10-4 M manganese(II) bromide solution is combined with 12.0 mL of a 2.53×10-4 M ammonium carbonate solution does a precipitate form?  (yes or no)

For these conditions the Reaction Quotient, Q, is equal to .

Solutions

Expert Solution

1)

Precipita will form

Q = 9.92 ×10-8

Explanation

Na3PO4(aq) + Cr(NO3)3(aq) ------> CrPO4(s) + 3NaNO3(aq)

Net ionic equation is

Cr3+(aq) + PO43-(aq) -------> CrPO4(s)

Ksp = [Cr3+]eq[PO43-]eq

reaction quotient , Q = [Cr3+​​​​​​]init[PO43-]init

[Cr3+]init = 4.38 ×10-4M/2 = 2.19×10-4M

[PO43-]init = 9.06 ×10- 4/2 = 4.53× 10-4M

Q = 2.19 × 10-4M × 4.53 ×10-4M

Q = 9.92 × 10-​​​​​​8M

Ksp of CrPO4 = 2.24 × 10-23

Q > Ksp

Therefore,

Precipitate will form

2)

Precipitate will form

Q = 3.54 ×10-8

Explanation

MnBr2(aq) + (NH4)2CO3(aq) --------> MnCO3(s) + 2NH4Br(aq)

Net ionic equation

Mn2+(aq) + CO32-(aq) --------> MnCO3(aq)

Ksp = [Mn2+]eq[CO32-]eq

Q = Mn2+]init[CO32-]init

[Mn2+]init = 5.83 ×10-4M/(30ml/18ml) = 3.50×10-4​​​​​​ M

[CO32-`] = 2.53 ×10-4/(30ml/12ml) = 1.01 × 10-4 M

Q = 3.50 ×10-4M × 1.01 ×10-4M

Q = 3.54 ×10-8

Ksp of MnCO3 = 1.8 × 10-11

Q > Ksp

Therefore

Precipitate will form

queen_honey_blossom answered 1 year ago
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