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A.) When 15.0 mL of a 8.98×10-4 M manganese(II) sulfate solution is combined with 18.0 mL...

A.)

When 15.0 mL of a 8.98×10-4 M manganese(II) sulfate solution is combined with 18.0 mL of a 9.68×10-4 M potassium hydroxide solution does a precipitate form?  (yes or no)

For these conditions the Reaction Quotient, Q, is equal to .

B.) When 18.0 mL of a 6.98×10-4M potassium sulfide solution is combined with 25.0 mL of a 7.19×10-4M zinc iodide solution does a precipitate form? (yes or no)

For these conditions the Reaction Quotient, Q, is equal to .

Solutions

Expert Solution

A)

We have 15.0 mL of a 8.98×10-4 M manganese(II) sulfate solution so,

millimoles of MnSO4 = 15ml*8.98×10-4 M = 134.7*10-4 millimoles (millimoles = molarity*volume in ml)

We also have 18.0 mL of a 9.68×10-4 M potassium hydroxide solution

millimoles of KOH = 18ml*9.68×10-4 M = 174.24*10-4 millimoles (millimoles = molarity*volume in ml)

After adding new volume = 15ml+18ml = 33ml

Mn+2 ions and OH- ions will form a precipitate of Mn(OH)2 if Q value which is [Mn+2][OH-]2 > Ksp

[Mn+2] = millimoles of MnSO4/new volume = 134.7*10-4 millimoles/33ml = 4.081*10-4 M

[OH-] = millimoles of KOH/new volume = 174.24*10-4 millimoles/33ml = 5.28*10-4 M

so, [Mn+2][OH-]2 = (4.081*10-4)*(5.28*10-4)2 = 113.771*10-12 which is greater than Ksp = 2*10-13 (taken from wiredchemist)

so, precipitate will form

B)

We have 18.0 mL of a 6.98×10-4M potassium sulfide solution so,

millimoles of K2S = 18ml*6.98×10-4 M = 125.64*10-4 millimoles (millimoles = molarity*volume in ml)

We also have 25.0 mL of a 7.19×10-4 M Zinc iodide solution

millimoles of ZnI2 = 25ml*7.19×10-4 M = 179.754*10-4 millimoles (millimoles = molarity*volume in ml)

After adding new volume = 18ml+25ml = 43ml

Zn+2 ions and S2- ions will form a precipitate of ZnS if Q value which is [Zn+2][S2-] > Ksp

[Zn+2] = millimoles of ZnI2/new volume =

179.754*10-4 millimoles/43ml = 4.18*10-4 M

[S2-] = millimoles of K2S/new volume = 125.64*10-4 millimoles/43ml = 2.92*10-4 M

so, [Zn+2][S2-]  = (4.18*10-4 M)*(2.92*10-4 M) = 12.2*10-8 which is greater than Ksp = 1*10-23 (taken from wiredchemist)

so, precipitate will form.

queen_honey_blossom answered 2 years ago
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