Calculate the pH of the buffer that results from mixing 51.2 mL of a 0.400 M...

Calculate the pH of the buffer that results from mixing 51.2 mL of a 0.400 M solution of HCHO2 and 12.9 mL of a 0.697 M solution of NaCHO2. The Ka value for HCHO2 is 1.8 × 10−4 . Express your answer to two decimal places. (a) 4.15 (b) 2.38 (c) 3.39 (d) 12.8 (e) None of the above

Expert Solution

no of moles of HCHO2 = molarity * volume in L

= 0.4*0.0512 = 0.02048 moles

no of moles of NaCHO2 = molarity * volume in L

= 0.697*0.0129

= 0.00899 moles

Pka = -logKa

= -log1.8*10^-4

= 3.7447

PH = Pka + log[NaCHO2]/[HCHO2]

= 3.7447 + log0.00899/0.02048

= 3.7447-0.3575 = 3.39

(c) 3.39 >>>>answer

queen_honey_blossom answered 2 years ago

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