From the following equilibrium constants, calculate the equilibrium constant for the reaction HO2CCO2H ----->2H+ + C2O-24...

From the following equilibrium constants, calculate the equilibrium constant for the reaction HO₂CCO₂H ----->2H⁺ + C₂O^-2₄

k1=5.6x10^-2

k2=5.4x10^-5

Expert Solution

HO₂CCO₂H (aq) ---------------> H^+ (aq) + HO₂CCO₂^- (aq) K1 = 5.6*10^-2

K1 = [H^+][HO₂CCO₂^-]/[HO₂CCO₂H]

HO₂CCO₂^- (aq) -------------> H^+ (aq) + C2O4^2- (aq) K2 = 5.4*10^-5

K2 = [H^+][C2O4^2-]/[HO₂CCO₂^-]

HO₂CCO₂H(aq) ----->2H⁺(aq) + C₂O₄^2-(aq)

K = [H^+]^2[C2O4^2-]/[HO₂CCO₂H]

K1*K2 = [H^+][HO₂CCO₂^-]/[HO₂CCO₂H] * [H^+][C2O4^2-]/[HO₂CCO₂^-]

K1*K2 = [H^+]^2[C2O4^2-]/[HO₂CCO₂H]

K1*K2 = K

K = K1*K2

= 5.6*10^-2 * 5.4*10^-5

= 3.024*10^-6

HO₂CCO₂H ----->2H⁺ + C₂O^-2₄ K = 3.024*10^-6 >>>>answer

queen_honey_blossom answered 2 years ago

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