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HClO is a weak acid (Ka = 4.0 × 10–8) and so the salt NaClO acts...

HClO is a weak acid (Ka = 4.0 × 10–8) and so the salt NaClO acts as a weak base. What is the pH of a solution that is 0.017 M in NaClO at 25 °C

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Expert Solution

Given :

Ka of HClO = 4.0 E-8

[NaClO] = 0.017 M

We know

[NaClO]= [ClO-] ….(salt dissociates completely)

Reaction of ClO- with water

            ClO- (aq)   + H2O (l)    ---- > HClO (aq)    + OH- (aq)

I           0.017                                       0                       0

C         -x                                    +x                             +x

E      (0.017-x)                                  x                        x

kb = 1.0 E-14 / ka

= 1.0 E-14 / 4.0 E-8

= 2.5 E -7

Les find x

2.5 E-7 = x2 / (0.017-x)

2.5 E-7 x 0.017 = x2         (By using 5 % approximation)

x = 6.52 E-5

x = [OH-] = 6.52 E-5

pOH = - log ([OH-]) = -log ( 6.52 E-5)

= 4.19

pH = 14 – pOH = 14- 4.19 = 9.81

pH = 9.81

queen_honey_blossom answered 1 year ago
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