In: Chemistry
HClO is a weak acid (Ka = 4.0
NaClO + H+ <---------> HClO + OH-
I 0.053 0 0
E 0.053-x +x +x
Kb = [OH-][HClO] / [NaClO]
Kb = Kw / Ka = (1 x 10^-14) / (4.0 x 10^-8) = 2.5 x 10^-7
2.5 x 10^-7 = x^2 / (0.053 -x )
2.5 x 10^-7 = x^2 / (0.053) [x is neglected as it is a small value]
x^2 = 1.325 x 10^-8
x = 1.15 x 10^-4 M
[OH-] = x = 1.15 x 10^-4 M
pOH = -log[OH-] = -log [1.15 x 10^-4]
pOH = 3.93
pH = 14-pOH
pH = 14-3.93 = 10.06
pH = 10.06