In: Chemistry
Consider the models you made for two compounds that have the formula C4H10O. Are there other isomers with this formula besides the ones you explored in the procedure? Would they have the same or different functional groups? Draw structures to provide examples. You do not have to name these compounds.
Here we shall draw all the possible isomers for the structure . Now, if we first determine its double bond equivalent(DBE), we can get to know whether the compounds will have any double bond and/or ring in their structures.
So, The DBE of = .
As the formula has a DBE =0, it will not contain any double bond/ring! Now, the compounds with this formula can be either an ether or an alcohol as both the class of compounds have similar general skeletal formula i.e. . So we have to draw four carbon alcohols and four carbon ethers for the molecule as below-
[NOTE- The two structural isomers you've drawn of this compound must be among the above 7 structures.]