In: Chemistry
Consider the models you made for two compounds that have the formula C4H10O. Are there other isomers with this formula besides the ones you explored in the procedure? Would they have the same or different functional groups? Draw structures to provide examples. You do not have to name these compounds.
Here we shall draw all the possible isomers for the
structure
. Now, if we first determine its double bond
equivalent(DBE), we can get to know whether the compounds will have
any double bond and/or ring in their structures.
So, The DBE of
=
.
As the formula
has a DBE =0, it will not contain any double
bond/ring! Now, the compounds with this
formula can be either an ether or an alcohol as both the class of
compounds have similar general skeletal formula i.e.
. So we have to draw four carbon alcohols and four
carbon ethers for the
molecule as below-
[NOTE- The two structural isomers you've drawn of this compound must be among the above 7 structures.]