In: Chemistry
If an aqueous solution of HNO3 is electrolyzed for 38.00 min at a steady current of 1.29 A, what volume of H2 (g) at 25.0oC and 0.99 atm will be collected at the cathode? vol H2 (L) =
Q= I *t
= 1.29*38*60
= 2941.19columbs
2 H^+ + 2e^-1--------------------> H2
2*96500 COLUMBS OF ELECTRICITY IS PASSED ---------------------------------------------- 22.4lit of H2 gas
2941.19 columbs of electricity passed ------------------------------------------------------------ ?
= 2941.19*22.4/(2*965000
= 0.034 litres of HYDROGEN GAS
P1=1 atm
V1= 0.034litres
T1= 273K
P2=0.99atm
T2= 298K
V2= ?
P1V1/T1= P2V2/T2
1*0.034/273=0.99*V2/298
V2= 0.037litres