In: Chemistry
If an aqueous solution of HNO3 is electrolyzed for 23.00 min at a steady current of 1.61 A, what volume of H2 (g) at 25.0oC and 0.99 atm will be collected at the cathode?
2HNO3 ------------> 2H^+ (aq) + 2NO3^-
2H^+ + 2e^- ----------------> H2
z =2
W = MCt/ZF
M = 2
C = 1.61A
t = 23min = 23*60sec = 1380sec
W = MCt/ZF
= 2*1.61*1380/2*96500 = 0.023g
PV = nRT
n = W/G.M.Wt = 0.023/2 = 0.0115moles
T = 250C = 25+273 = 298K
P = 0.99atm
PV = nRT
V = nRT/P
= 0.0115*0.0821*298/0.99 = 0.284L >>>>anwer