If an aqueous solution of HNO3 is electrolyzed for 23.00 min at a steady current of...

If an aqueous solution of HNO3 is electrolyzed for 23.00 min at a steady current of 1.61 A, what volume of H2 (g) at 25.0oC and 0.99 atm will be collected at the cathode?

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Expert Solution

2HNO3 ------------> 2H^+ (aq) + 2NO3^-

2H^+ + 2e^- ----------------> H2

z =2

W = MCt/ZF

M = 2

C = 1.61A

t = 23min = 23*60sec = 1380sec

W = MCt/ZF

= 2*1.61*1380/2*96500 = 0.023g

PV = nRT

n = W/G.M.Wt = 0.023/2 = 0.0115moles

T = 25⁰C = 25+273 = 298K

P = 0.99atm

PV = nRT

V = nRT/P

= 0.0115*0.0821*298/0.99 = 0.284L >>>>anwer

queen_honey_blossom answered 1 year ago

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