In: Chemistry
INTEGRATED SELF DIRECTED WORK
INSTRUCTIONS
Prepare a report and submit asper the deadline.
References should be Harvard style.
Report must be submitted as per the deadline.
Case:
A mixture containing 45% benzene (b) and 55% toluene (t) by mass is fed to a distillation column. an overhead stream of 95 wt% b is produced, and 8% of the benzene fed to the column leaves in the bottom stream, the feed rate is 2000 kg/h.
ENGINEERING MATERIALS
1. Suggest the Suitable Material to fabricate the Distillation column.
2. Identify the corrosive behavior of chemicals to the selected material and calculate the corrosion allowances for thickness of the column.
3. Explain the suitable maintenance procedure involved in distillation column.
PROCESS CALCULATION
1. Write the hypothesis for the above distillation column calculations.
2. Determine the overhead flow rate and the mass flow rates of benzene and toluene in the bottom stream.
3. Draw the flowsheet and investigate the required output streams.
TECHNICAL MATHEMATICS
Draw the graph for Temperature Vs Vapor pressure Benzene and Vapor pressure of toluene.
Vapor pressure data of benzene and toluene
Temperature |
Benzene (mmHg) |
Toluene(mmHg) |
80.1 |
760 |
- |
85 |
877 |
345 |
90 |
1016 |
405 |
95 |
1168 |
475 |
100 |
1344 |
557 |
105 |
1532 |
645 |
Assume Feed (F) is directly proportional to the Distillate(3 + 4 = 7 Marks)
F=f (D)
f (D)= 4D3 5D2 + 2D + 8.
Determine the interval for which the distillate is increases, decreases and constant.
Show that whether the feed F is max, min or neither. Also determine the possible value of F.
1.Carbon steel used for fabrication of collumn. Because it is cheaper and for benzene -toluene seperation it is suitable.
2.The corrosion allowance appears to have been initially set at some arbitrary value and could range from about 0.100 to 0.500 inches. A value of 0.10- inches was commonly used as the corrosion allowance for carbon-steel.
The following equation used to find corrosion allowance.
It =Im + (ri+ro)t
It =total wall thickness
Im = mechanical calculation wall thickness
ri =inside corrosion allowance
ro =outside corrosion allowance
t=design project life.
Process calculation:
Feed:
F=2000 kg/hr
xbenzene =0.45
xtoluene = 0.55
Distillate:
xD,ben = 0.95
xD,tol = 0.5
Distillate mass flow rate=D
Bottom:
In bottom 8% of benzene is there.
So in bottom product benzene = 0.08*benzene fed in column
benzene in feed = 0.45*2000 =900 kg/hr
So Wb = 0.08*900 = 72 kg/hr
Now benzene balnce around collumn
benzene in feed=benzene in distillate+benzene in bottom
900 = 0.95*D+72
(2) So overhead product D =871.57 kg/hr
Now overall material balance
F=D+W
2000=871.57+W
W=1128.43 kg/hr
So in Bottom toluene =1128.43-72=1056.43 kg/hr