The percent yield for the following reaction is 95.4% 2 Al + 6 HCl ----> 3...

The percent yield for the following reaction is 95.4%

2 Al + 6 HCl ----> 3 H₂ + 2 AlCl₃

What volume of 12.6 M HCl is needed to actually produce 30.0 g of H2? Assume Al is in excess.

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queen_honey_blossom answered 1 year ago

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