An ideal gas initally at 343.15K and 1 barundergoes a three step mechanically irreversible cycle in...

An ideal gas initally at 343.15K and 1 barundergoes a three step mechanically irreversible cycle in a closed system. In step 1-2, volume decreases at adiabatically to 423.15K. In step 2-3, temperature decreases at a constant pressure to 343.15K. In step 3-1, the gas reutrns isothermally to it’s initial state. Take Cp=(7/2)R and Cv=(5/2)R. Calculate Q and W for each step of cycle. Energy efficiency is 80%. (P T U H changes same as reversable cycle but Q and W are different)

Expert Solution

Amanda K answered 2 years ago

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