Question

In: Chemistry

The vapor pressures of SO2(s) and SO2(l) in the vicinity of the triple point are given...

The vapor pressures of SO2(s) and SO2(l) in the vicinity of the triple point are given by the equations, Ln (P/torr) = 23.9812 - 4244.7/T and Ln (P/torr) = 19.2453 - 3298.4/T, respectively, where T is absolute temperature. (i)Determine from these equations the three phase change enthalpies, ∆subH°, ∆vapH° and ∆fusH°.

Solutions

Expert Solution

Recall that in equilibrium; especially in vapor-liquid equilibriums, we can use Clasius Clapyeron combination equation in order to relate two points in the same equilibrium line.

The equation is given as:

ln(P2/P1) = -dHvap/R*(1/T2-1/T1)

Where

P2,P1 = vapor pressure at point 1 and 2

dH = Enthalpy of vaporization, typically reported in kJ/mol, but we need to use J/mol

R = 8.314 J/mol K

T1,T2 = Saturation temperature at point 1 and 2

Therefore, we need at least 4 variables in order to solve this.

Substitute all known data:

ln(P2/P1) = -dHvap/R*(1/T2-1/T1)

Therefore, we can get Hphase/R from the slopes:

Ln (P/torr) = 23.9812 - 4244.7/T

Ln (P/torr) = 19.2453 - 3298.4/T

Slope 1 = 4244.7

Slope 2 = 3298.4

Hs1 = 4244.7*8.314 = 35290.4 J/mol

Hs2 = 3298.4*8.314 = 27422.89 J/mol

note that

Hs1 = solid/vapor; Hs2 = lqidui/vapor

Hliqud-solid = 35290.4 - 27422.89 = 7867.51

then

Hvap = 27422.89 J/mol = 27.42 kJ/mol

Hfus = 7867.51 J/mol = 78.67 kJ/mol

Hsub = 35290.4 J/mol = 35.29  kJ/mol


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