Question
In: Chemistry
Vapor Pressures of a solid and liquid ammonia near the triple point are given by: log...
Vapor Pressures of a solid and liquid ammonia near the triple point are given by: log P solid/ torr=10.00-1630 K/T log P liquid / torr=8.46-1330 K/T Calculate the ratio of the slopes of the sublimation and vapor pressure curves at the triple point.
Solutions
Expert Solution
Clausius - Clapeyron equation :
dP/dT = L / TΔV
L is the specific latent heat
Assuming that the ammonia vapor obeys the ideal gas law and the
volume of the solid and the liquid is negligibly small compared to
the volume of the gas, we can get
ln P = (- L / RT) + constant ------------ (1)
2.303 ln P = 10 - (1630 K / T ) ------------ (2)
compare equations 1 and 2 (the slope part, the one part which is in
brackets) ,
as vapor pressure of solid is considered L = Lsub
1630 K / 2.303 = Lsub / R
1630 K R / 2.303 = Lsub
K = 3.12 *104 J/mol for sublimation R = 8.314 J /mol
K
707 * 3.12*104 * 8.314 = Lsub
Lsub = 183393537.6 J/ K = 183393.53 kJ/K
ratio of slopes of sublimation and vapor pressure curve of solid
ammonia,
( Lsub /R ) / (1630K/2.303) =
0.9989
similarly it can be done for Lvap ,
2.303 ln P = 8.46 - (1330 K / T ) ---------------(3)
ln P = (- Lsub / RT) + constant ------------- (1)
K = 2.55 *104 for equation 3
ratio of the slopes of sublimation and vapor pressure curve of
liquid ammonia,
(Lsub / R ) / (1330K/2.303) = 1.49787
queen_honey_blossom answered 1 year agoRelated Solutions
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