Question

In: Finance

Assume an initial underlying stock price of $20, an exercise price of $20, a time to...

Assume an initial underlying stock price of $20, an exercise price of $20, a time to expiration of 3 months, a risk free rate of 12% and a underlying stock return variance of 16%. If the risk free rate decreased to 6% and assuming other variables are held constant, the call option value would

A) increase

B) remain the same

C) decrease

D) indeterminate from the information given

Solutions

Expert Solution

Std dev = variance^(1/2) = 0.16^0.5 = 0.4 = 40%

As per Black Scholes Model
Value of call option = S*N(d1)-N(d2)*K*e^(-r*t)
Where
S = Current price = 20
t = time to expiry = 0.25
K = Strike price = 20
r = Risk free rate = 12.0%
q = Dividend Yield = 0.00%
σ = Std dev = 40%
d1 = (ln(S/K)+(r-q+σ^2/2)*t)/(σ*t^(1/2)
d1 = (ln(20/20)+(0.12-0+0.4^2/2)*0.25)/(0.4*0.25^(1/2))
d1 = 0.25
d2 = d1-σ*t^(1/2)
d2 =0.25-0.4*0.25^(1/2)
d2 = 0.05
N(d1) = Cumulative standard normal dist. of d1
N(d1) =0.598706
N(d2) = Cumulative standard normal dist. of d2
N(d2) =0.519939
Value of call= 20*0.598706-0.519939*20*e^(-0.12*0.25)
Value of call= 1.88
As per Black Scholes Model
Value of call option = S*N(d1)-N(d2)*K*e^(-r*t)
Where
S = Current price = 20
t = time to expiry = 0.25
K = Strike price = 20
r = Risk free rate = 6.0%
q = Dividend Yield = 0.00%
σ = Std dev = 40%
d1 = (ln(S/K)+(r-q+σ^2/2)*t)/(σ*t^(1/2)
d1 = (ln(20/20)+(0.06-0+0.4^2/2)*0.25)/(0.4*0.25^(1/2))
d1 = 0.175
d2 = d1-σ*t^(1/2)
d2 =0.175-0.4*0.25^(1/2)
d2 = -0.025
N(d1) = Cumulative standard normal dist. of d1
N(d1) =0.56946
N(d2) = Cumulative standard normal dist. of d2
N(d2) =0.490027
Value of call= 20*0.56946-0.490027*20*e^(-0.06*0.25)
Value of call= 1.73

Price has decreased with r = 6% compared to r = 12%


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