In: Statistics and Probability
Use technology to construct the confidence intervals for the population variance
sigmaσsquared2
and the population standard deviation
sigmaσ.
Assume the sample is taken from a normally distributed population.
cequals=0.95
ssquared2equals=12.96
nequals=25
Solution :
Given that,
Point estimate = s2 = 12.96
2L = 2/2,df = 39.364
2R = 21 - /2,df = 12.401
The 95% confidence interval for 2 is,
(n - 1)s2 / 2/2 < 2 < (n - 1)s2 / 21 - /2
24 * 12.96 / 39.364 < 2 < 24 * 12.96 / 12.401
7.90 < 2 < 25.08
(7.90 , 25.08)
The 95% confidence interval for is,
2.81 < < 5.01
(2.81 , 5.01)