In: Statistics and Probability
Use technology to construct the confidence intervals for the population variance
sigmaσsquared2
and the population standard deviation
sigmaσ.
Assume the sample is taken from a normally distributed population.
cequals=0.95
ssquared2equals=12.96
nequals=25
Solution :
Given that,
Point estimate = s2 = 12.96
2L
=
2
/2,df
= 39.364
2R
=
21 -
/2,df = 12.401
The 95% confidence interval for
2 is,
(n - 1)s2 /
2
/2
<
2 < (n - 1)s2 /
21 -
/2
24 * 12.96 / 39.364 <
2 < 24 * 12.96 / 12.401
7.90 <
2 < 25.08
(7.90 , 25.08)
The 95% confidence interval for
is,
2.81 <
< 5.01
(2.81 , 5.01)