In: Statistics and Probability
Use technology to construct the confidence intervals for the population variance sigmaσsquared2 and the population standard deviation sigmaσ. Assume the sample is taken from a normally distributed population. c=0.99, s =35, n=19
What is the confidence interval for the population variance?
What is the confidence interval for the population standard deviation?
Solution :
Given that,
s = 35
Point estimate = s2 = 1225
2R = 2/2,df = 37.156
2L = 21 - /2,df = 6.265
The 99% confidence interval for 2 is,
(n - 1)s2 / 2/2 < 2 < (n - 1)s2 / 21 - /2
(18) (1225) / 37.156 < 2 < (18) (1225) / 6.265
593.44 < 2 < 3519 .67
(593.44 , 3519.67)
s = 35
s2 = 1225
2R = 2/2,df = 37.156
2L = 21 - /2,df = 6.265
The 99% confidence interval for is,
(n - 1)s2 / 2/2 < < (n - 1)s2 / 21 - /2
(18)(1225) / 37.156 < < (18)(1225) / 6.265
24.36 < < 59.33
(24.36 , 59.33)