In: Chemistry
reagent | Molecular Weight | Gram | mmol | equivalents | d | mL |
hydroquinone | 110 | 1.0 | xxxx | xxx | ||
acetic anhydride | 102 | 1 | 3.1 | 1.08 | ||
phosphoric acid | 98 | 1.85 | 0.05 | |||
THEORETICAL PRODUCT | XXXXXXXXXXX | XXXX | XXX | XXXXXXXX | xxxxx | XX |
4-(acetyloxy) phenylacetate | xxxxxxxxxx | xxxx | xxxx | |||
acetic acid | xxxxxxxxxx | 1.049 |
Please show step by step solution. Thanks!
reagent | Molecular Weight | Gram | mmol | equivalents | d | mL |
hydroquinone | 110 | 0.347 g | 3.1 | 1.0 | xxxx | xxx |
acetic anhydride | 102 | 1 | 9.8 | 3.1 | 1.08 | 0.925 |
phosphoric acid | 98 | 0.0925 | 0.9 | 0.29 | 1.85 | 0.05 |
THEORETICAL PRODUCT | XXXXXXXXXXX | XXXX | XXX | XXXXXXXX | xxxxx | XX |
4-(acetyloxy) phenylacetate | 194.18 | 0.616 g | 3.1 | xxxxxxxxxx | xxxx | xxxx |
acetic acid | 60 | 0.74 g | 12.3 | xxxxxxxxxx | 1.049 | 0.77 |
answers filled table.
first we want to know hydroquinone wt and moles using aceticanhydride wt and molecular weight
as per above reaction equvalents 3.1 more aceticanhydride compare to hydroquinone 1, so
if calculate same ratio
aceticanhydride weight/ molecular weight*1000, 1/102 *1000 =9.80
acetic anhydride moles =9.8 millimoles ,
when grams to mls convertion (mass divided by with density) = 1/1.08
=0.925 ml
so 9.80 three times more moles so 9.8/3.1 = 3.1
hydroquinone =3.1*110/100 (millimoles to moles)
wt =0.347 g
millimoles already know 3.1 millimoles.
phosphoric acid : when mls to grams convertion (mls multiply with density) = 0.05*1.85
0.0925 g
we know moles weight/molecular weight
=0.0925/98*1000
=0.9 millimoles
equvalents = phosphoricacid milli moles/hydroquinone millimoles (because considered hydroquinone as 1), all caluculations with respect to the hydroquinone
=0.9/3.1
=0.29 equivalents.
same as in product expected product 4-(acetyloxy) phenylacetate molecular weight 194.18
to hydroquinone actylation will takes place form as 4-(acetyloxy) phenylacetate,
0.347/110*194.18
=0.61 g
millimoles same as hydroquinone
=0.61/194.18*1000
=3.1 millimoles
actic acid form from excess of acetic anhydride , acetic acid molecular weight 60
this will give one mole aceticanhydride two moles of acetic acid.