In: Statistics and Probability
Consider the following competing hypotheses:
H0: ρxy = 0
HA: ρxy ≠ 0
The sample consists of 16 observations and the sample correlation
coefficient is 0.27. [You may find it useful to reference
the t table.]
a-1. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.)
Given ,
Sample correlation coefficient = r = 0.27
Sample size = n = 16
Hypothesis :
Two tailed test.
Test statistic -
Critical value :
Let, significance level = = 0.05
Degrees of freedom = df = n - 2 = 16 - 2 = 14
Using Excel, =TINV( , df ) , This function returns two tailed inverse of t distribution
=TINV( 0.05 , 14 ) = 2.145
So, t critical value's for this two tailed test is ,
and
Decision about null hypothesis :
Rule : Reject null hypothesis if test statistic t < - 2.145 or t > 2.145
It is observed that test statistic t = 1.049 is less than 2.145 and greater than -2.145.
So, Do not reject null hypothesis.
Conclusion :
There is not sufficient evidence to conclude that variables are correlated.