Question

In: Chemistry

Here are four problems (5 pts each) involving the calculation of DG°' for metabolic reactions we...

Here are four problems (5 pts each) involving the calculation of DG°' for metabolic reactions we have discussed, based on experimentally determined redox potentials. Calculate the DG°' for each reaction using the equation DG°' = -nFDE0' and the values for E0' given in Table 1. Show your work and circle your answer.

Table 1. Reduction potentials for reduction half reactions:

1/2 O2 + 2H+ + 2e- ® H2O                                              E0' = +0.82 V

fumarate + 2H+ + 2e- ® succinate                                  E0' = +0.03 V

oxaloacetate + 2H+ + 2e- ® malate                                 E0' = -0.17 V

pyruvate + 2H+ + 2e- ® lactate                                       E0' = -0.19 V

a-ketoglutarate + CO2 + 2H+ + 2e- ® isocitrate               E0' = -0.38 V

FAD + 2H+ + 2e- ® FADH2                                             E0' = -0.22 V

NAD+ + 2H+ + 2e- ® NADH + H+                                    E0' = -0.32 V

CoQ + 2H+ + 2e- ® CoQH2                                            E0' = +0.06 V

Problem 3. malate + NAD+ ® oxaloacetate + NADH + H+

Problem 4. FADH2 + CoQ ® FAD + CoQH2

Solutions

Expert Solution

malate + NAD+ -------------------> oxaloacetate + NADH + H+

malate -----------------> oxaloacetate + 2H+ + 2e-           E0 = 0.17V

NAD+ + 2H+ + 2e- ---------> NADH + H+                                    E0' = -0.32 V

-------------------------------------------------------------------------------------------------------------

malate + NAD+ -------------------> oxaloacetate + NADH + H+     E0cell= -0.15V

DG°' = -nFDE0'

        = -2*96500*-0.15   = 28950J

FADH2 + CoQ ------------> FAD + CoQH2

FADH2   ------------> FAD + 2H+ + 2e-      E0 = 0.22V

CoQ + 2H+ + 2e- -----------> CoQH2        E0' = +0.06 V

---------------------------------------------------------------------

FADH2 + CoQ ------------> FAD + CoQH2   E0cell =0.28V

DG°' = -nFDE0'

        = -2*96500*0.28 = -54040J


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