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In: Chemistry

Here are four problems (5 pts each) involving the calculation of DG°' for metabolic reactions we...

Here are four problems (5 pts each) involving the calculation of DG°' for metabolic reactions we have discussed, based on experimentally determined redox potentials. Calculate the DG°' for each reaction using the equation DG°' = -nFDE0' and the values for E0' given in Table 1. Show your work and circle your answer.

Table 1. Reduction potentials for reduction half reactions:

1/2 O2 + 2H+ + 2e- ® H2O                                              E0' = +0.82 V

fumarate + 2H+ + 2e- ® succinate                                  E0' = +0.03 V

oxaloacetate + 2H+ + 2e- ® malate                                 E0' = -0.17 V

pyruvate + 2H+ + 2e- ® lactate                                       E0' = -0.19 V

a-ketoglutarate + CO2 + 2H+ + 2e- ® isocitrate               E0' = -0.38 V

FAD + 2H+ + 2e- ® FADH2                                             E0' = -0.22 V

NAD+ + 2H+ + 2e- ® NADH + H+                                    E0' = -0.32 V

CoQ + 2H+ + 2e- ® CoQH2                                            E0' = +0.06 V

Problem 1. isocitrate + NAD+ ® a-ketoglutarate + CO2 + NADH

Problem 2. succinate + FAD ® fumarate + FADH2

Solutions

Expert Solution

Problem 1. isocitrate + NAD+---------> a-ketoglutarate + CO2 + NADH

                 isocitrate ---------------> a-ketoglutarate + CO2 + 2H+ + 2e-                 E0 = 0.38V

                NAD+ + 2H+ + 2e-------------> NADH + H+                                   E0' = -0.32 V

   ----------------------------------------------------------------------------------------------------------------------------------

                     isocitrate + NAD+---------> a-ketoglutarate + CO2 + NADH               E0 cell = 0.06V

                   G = -nE0cell *F

                              = -2*0.06*96500   = -11580J

Problem 2. succinate + FAD --------------->fumarate + FADH2

                        succinate ------------------> fumarate + 2H+ + 2e-    E0 = -0.03V

               FAD + 2H+ + 2e- ----------> FADH2                                             E0' = -0.22 V

--------------------------------------------------------------------------------------------------- ------------------

    succinate + FAD --------------->fumarate + FADH2             E 0cell =- 0.25 V

                           G = -nE0cell *F

                                    = -2*-0.25*96500   = 48250J

                       

                


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