In: Statistics and Probability
he following table shows site type and type of pottery for a random sample of 628 sherds at an archaeological location.
Pottery Type | ||||
Site Type | Mesa Verde Black-on-White |
McElmo Black-on-White |
Mancos Black-on-White |
Row Total |
Mesa Top | 75 | 63 | 51 | 189 |
Cliff-Talus | 82 | 68 | 63 | 213 |
Canyon Bench | 94 | 72 | 60 | 226 |
Column Total | 251 | 203 | 174 | 628 |
Use a chi-square test to determine if site type and pottery type are independent at the 0.01 level of significance.
Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places.)
Hypotheses are:
H0:; The site type and pottery type are independent.
Ha:; The site type and pottery type are not independent.
Expected frequencies will be calculated as follows:
Following table shows the expected frequencies:
Mesa Verde | McElmo | Mancos | Row total | |
Mesa Top | 75.54 | 61.094 | 52.366 | 189 |
Cliff-Talus | 85.132 | 68.852 | 59.016 | 213 |
Canyon Bench | 90.328 | 73.054 | 62.618 | 226 |
Column Total | 251 | 203 | 174 | 628 |
Following table shows the calculations for chi square test statistics:
O | E | (O-E)^2/E |
75 | 75.54 | 0.003860207 |
82 | 85.132 | 0.115226049 |
94 | 90.328 | 0.149273581 |
63 | 61.094 | 0.059463057 |
68 | 68.852 | 0.010542962 |
72 | 73.054 | 0.015206779 |
51 | 52.366 | 0.035632968 |
63 | 59.016 | 0.268948353 |
60 | 62.618 | 0.109456131 |
Total | 0.767610085 |
Following is the test statistics:
Degree of freedom: df =( number of rows -1)*(number of columns-1) = (3-1)*(3-1)=4
The p-value is: 0.9427
Since p-value is greater than 0.01 so we fail to reject the null hypothesis. That is we can conclude that site type and pottery type are independent.
Excel function used for p-value: "=CHIDIST(0.77, 4)"