In: Statistics and Probability
The following table shows site type and type of pottery for a random sample of 628 sherds at an archaeological location.
Pottery Type | ||||
Site Type | Mesa Verde Black-on-White |
McElmo Black-on-White |
Mancos Black-on-White |
Row Total |
Mesa Top | 77 | 62 | 50 | 189 |
Cliff-Talus | 83 | 75 | 55 | 213 |
Canyon Bench | 92 | 72 | 62 | 226 |
Column Total | 252 | 209 | 167 | 628 |
Use a chi-square test to determine if site type and pottery type are independent at the 0.01 level of significance.
(a) What is the level of significance?
State the null and alternate hypotheses.
H0: Site type and pottery are not
independent.
H1: Site type and pottery are independent.
H0: Site type and pottery are
independent.
H1: Site type and pottery are
independent.
H0: Site type and pottery are
not independent.
H1: Site type and pottery are not
independent.
H0: Site type and pottery are
independent.
H1: Site type and pottery are not
independent.
(b) Find the value of the chi-square statistic for the sample.
(Round the expected frequencies to at least three decimal places.
Round the test statistic to three decimal places.)
Are all the expected frequencies greater than 5?
What sampling distribution will you use?
uniform
Student's t
normal
binomial
chi-square
What are the degrees of freedom?
(c) Find or estimate the P-value of the sample test
statistic. (Round your answer to three decimal places.)
p-value > 0.1000
.050 < p-value < 0.100
0.025 < p-value < 0.0500
.010 < p-value < 0.0250
.005 < p-value < 0.010
p-value < 0.005
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis of independence?
Since the P-value > α, we fail to reject the null hypothesis.
Since the P-value > α, we reject the null hypothesis.
Since the P-value ≤ α, we reject the null hypothesis.
Since the P-value ≤ α, we fail to reject the null hypothesis.
(e) Interpret your conclusion in the context of the
application.
At the 1% level of significance, there is sufficient evidence to conclude that site and pottery type are not independent.At the 1% level of significance, there is insufficient evidence to conclude that site and pottery type are not independent.
Solution:
Here, we have to use chi square test for independence of two categorical variables.
(a) What is the level of significance?
We are given level of significance = α = 0.01
State the null and alternate hypotheses.
Null hypothesis: H0: Site type and pottery are independent.
Alternative hypothesis: H1: Site type and pottery are not independent.
(b) Find the value of the chi-square statistic for the sample.
Test statistic formula is given as below:
Chi square = ∑[(O – E)^2/E]
Where, O is observed frequencies and E is expected frequencies.
E = row total * column total / Grand total
α = 0.01
Critical value = 13.2767
(by using Chi square table or excel)
Calculation tables for test statistic are given as below:
Observed Frequencies (O) |
||||
Pottery Type |
||||
Site type |
Messa |
McElmo |
Mancos |
Total |
Mesa top |
77 |
62 |
50 |
189 |
Cliff-Talus |
83 |
75 |
55 |
213 |
Canyon Bench |
92 |
72 |
62 |
226 |
Total |
252 |
209 |
167 |
628 |
Expected Frequencies (E) |
||||
Pottery Type |
||||
Site type |
Messa |
McElmo |
Mancos |
Total |
Mesa top |
75.84076 |
62.89968 |
50.25955 |
189 |
Cliff-Talus |
85.47134 |
70.88694 |
56.64172 |
213 |
Canyon Bench |
90.6879 |
75.21338 |
60.09873 |
226 |
Total |
252 |
209 |
167 |
628 |
Calculations |
||
(O - E) |
||
1.159236 |
-0.89968 |
-0.25955 |
-2.47134 |
4.113057 |
-1.64172 |
1.312102 |
-3.21338 |
1.901274 |
(O - E)^2/E |
||
0.017719 |
0.012869 |
0.00134 |
0.071457 |
0.238651 |
0.047584 |
0.018984 |
0.137287 |
0.060148 |
Chi square = ∑[(O – E)^2/E] = 0.606039
Chi square statistic = 0.606
Are all the expected frequencies greater than 5?
Yes, all expected frequencies are greater than 5.
What sampling distribution will you use?
chi-square
What are the degrees of freedom?
We are given
Number of rows = r = 3
Number of columns = c = 3
Degrees of freedom = df = (r – 1)*(c – 1) = 2*2 = 4
(c) Find or estimate the P-value of the sample test statistic.
P-value = 0.96239
(By using Chi square table or excel)
p-value > 0.1000
(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis of independence?
P-value > α = 0.01
Since the P-value > α, we fail to reject the null hypothesis.
(e) Interpret your conclusion in the context of the application.
At the 1% level of significance, there is insufficient evidence to conclude that site and pottery type are not independent.
There is sufficient evidence to conclude that Site type and pottery are independent.