Question

In: Physics

when the current[ =Ⅰ ] flowing through the wire in the direction of the z-axis, magnetic...

when the current[ =Ⅰ ] flowing through the wire in the direction of the z-axis, magnetic vector potential is following that

A = ez[μ*ln(1/ρ)/2π]

show that magnetic field B is same as B = eφ[μI/2πρ]

Solutions

Expert Solution

We have current through th wire in the direction of

we have,

magnetic vector potential due to this current wire given as,

where,

unit vector in the direction of z-axis,

magnetic field strength is given curl of vectro potential as,

where,

,

where,

are unit vectors in cylindrical coordinate system.

Using the distributive property of the cross product we get,

We have,

,    and  

Using these values of cross-product of unit vectors in the above equation we get,

______________________________relation 1

Now we will solve partial derivatives in the above equation,

Using    in above equation we get,

______________________relation 2

_________ relation 3

Using these values of partial derivatives in relations 2 and 3 , in relation 1 we get,

hence we proved that magnetic field arround conductor is given as,

,


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