A long straight wire carrying a current I = 1.4 amps flowing in the +y direction...

A long straight wire carrying a current I = 1.4 amps flowing in the +y direction has a rectangular wire to its right. The length of the wire (parallel to the straight wire) is .7 m and its width is .4 m. The left side of the rectangular wire is originally .5 meters away from the straight wire. A force of 8 Newtons to the right is applied to the rectangular wire which is initially at rest. Assume the resistance of the rectangular wire is 12 ohms and its mass is 2 kg. Find the Emf, the current and the force on the rectangular wire due to the straight wire when its left side has reached 2.0 meters away from the straight wire. What would happen if instead of the rectangular wire moving, the current in the straight wire was changing according to the equation I = .3t² amps flowing in the +y direction? Find the Emf, the current and the force on the rectangular wire due to the straight wire after 6 seconds.

Answers Should Be:

Emf = -56.5 nVolts, I = 4.71 nAmps clockwise, Ftotal = 7.69 x 10-17 N to the left

Emf =.296 μVolts, I = .0247 μAmps counterclockwise, Ftotal = .0332 pN to the right

Expert Solution

genius_generous answered 2 years ago

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