The equilibrium constant for the reaction, 2 Fe3+(aq) + Hg22+(aq) <=> 2 Fe2+(aq) + 2 Hg2+(aq)...

The equilibrium constant for the reaction, 2 Fe³⁺(aq) + Hg2²⁺(aq) <=> 2 Fe²⁺(aq) + 2 Hg²⁺(aq) is 9.1 x 10-6(aq) at 298 K.

Calculate ΔG in J when

{Fe³⁺(aq)} = 0.725

{Hg2²⁺(aq)} = 0.022

{Fe²⁺(aq)} = 0.033

{Hg²⁺(aq)} = 0.056

Solutions

Expert Solution

queen_honey_blossom answered 1 year ago

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