Question

In: Statistics and Probability

In test of a computer component, it is found that the mean between failures is 520...

In test of a computer component, it is found that the mean between failures is 520 hours. A modification is made which is supposed to increase the time between failures. Tests on a random sample of 8 modified components resulted in the following times (in hours) between failures. Use a 0.05 significance level to test the claim that the mean time between failures is greater than 520 hours. Assume that the population is normally distributed. 518, 548, 561, 523, 536, 499, 538, 557 (please show work and TI-84 plus steps for comparison)

a. Compute the mean and standard deviation of the data.

b. State null and alternative hypotheses. Define the parameter.

c. Show the graph and label the p-value in graph.

d. Compare the p-value vs. ?.

e. State the decision and conclusion.

Solutions

Expert Solution


Related Solutions

In test of a computer component, it is found that the mean between failures is 520...
In test of a computer component, it is found that the mean between failures is 520 hours. A modification is made which is supposed to increase the time between failures. Tests on a random sample of 8 modified components resulted in the following times (in hours) between failures. Use a 0.05 significance level to test the claim that the mean time between failures is greater than 520 hours. Assume that the population is normally distributed. 518, 548, 561, 523, 536,...
A modification is made to a computer component to try to increase its mean time between...
A modification is made to a computer component to try to increase its mean time between failures, which was originally 520 hours. Tests on a simple random sample of 10 modified components resulted in the following times (in hours) between failures. Assume that the sample comes from a normally distributed population. 518 548 561 523 536 499 538 557 528 563 At the 0.05 significance level, test the claim that, with the modified component, the mean time between failures is...
A hard Drive manufacturers is required to ensure that the mean time between failures for its...
A hard Drive manufacturers is required to ensure that the mean time between failures for its new hard drive is 1 million hours. A stress test is designed that can simulate the workload at a much faster rate. The test is designed so that a test lasting 10 days is equivalent to the hard drive lasting 1 million hours. In stress tests of 15 hard drives, the average is 9.5 days with a standard deviation of 1 day. Can the...
In a study of 789 randomly selected medical malpractice​ lawsuits, it was found that 520 of...
In a study of 789 randomly selected medical malpractice​ lawsuits, it was found that 520 of them were dropped or dismissed. Use a 0.01 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed.
Of all failures of a certain type of computer hard drive, it is determined that in...
Of all failures of a certain type of computer hard drive, it is determined that in 15% of them only the sector containing the file allocation table is damaged (F), in 65% of them only nonessential sectors are damaged (S), and in 20% of the case , both the allocation sector and one or more essential sectors are damaged.A failed drive is selected at random and examined. a)Represent this information in Venn Diagram b)Given that the drive has damaged file...
Compute 95% bootstrap confidence intervals for the mean time between failures 1/λ by the standard normal,...
Compute 95% bootstrap confidence intervals for the mean time between failures 1/λ by the standard normal, basic, percentile, and BCa methods. Compare the intervals and explain why they may differ. 3, 5, 7, 18, 43, 85, 91, 98, 100, 130, 230, 487. Use R software and provide with codes
In a survey of 520 potential jurors, one study found that 360 were regular watchers of...
In a survey of 520 potential jurors, one study found that 360 were regular watchers of at least one crime-scene forensics television series. (a) Assuming that it is reasonable to regard this sample of 520 potential jurors as representative of potential jurors in the United States, use the given information to construct a 95% confidence interval for the true proportion of potential jurors who regularly watch at least one crime-scene investigation series.
The mean Verbal SAT score for the population of first students at Radford is 520. The...
The mean Verbal SAT score for the population of first students at Radford is 520. The standard deviation of scores in this population is 95. An investigator believes that the mean Verbal SAT of first year psychology majors is significantly different from the mean score of the population. The mean of a sample of 36 first year psychology majors is 548. Please test the investigator's prediction using an alpha level of .05. a. Please state both the null and alternative...
A particular fruit's weights are normally distributed, with a mean of 520 grams and a standard...
A particular fruit's weights are normally distributed, with a mean of 520 grams and a standard deviation of 40 grams. If you pick 27 fruits at random, then 11% of the time, their mean weight will be greater than how many grams?
From her firm's computer telephone log, an executive found that the mean length of 60 telephone...
From her firm's computer telephone log, an executive found that the mean length of 60 telephone calls during July was 4.54 minutes with a standard deviation of 5.07 minutes. She vowed to make an effort to reduce the length of calls. The August phone log showed 42 telephone calls whose mean was 2.408 minutes with a standard deviation of 2.293 minutes. (a) Choose the appropriate hypotheses assuming the desire to reduce the length of calls. Assume µ1 is the average...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT