Compute 95% bootstrap confidence intervals for the mean time between failures 1/λ by the standard normal,...

Compute 95% bootstrap confidence intervals for the mean time between failures 1/λ by the standard normal, basic, percentile, and BCa methods. Compare the intervals and explain why they may differ.

3, 5, 7, 18, 43, 85, 91, 98, 100, 130, 230, 487.

Use R software and provide with codes

Solutions

Expert Solution

R-code:

The 95% confidence interval for 1/lambda is between 23.5 and 170.6 by Basic method

The 95% confidence interval for 1/lambda is between 45.6 and 192.7 by Percentile method

The 95% confidence interval for 1/lambda is between 54.8 and 222.9 by BCa method

orchestra answered 1 year ago

Next > < Previous

Related Solutions

. It is desired to design 95 confidence intervals for the ratio between standard deviation of...

. It is desired to design 95 confidence intervals for the ratio between standard deviation of two electroplating lines in a micro-electro-mechanical system (MEMS) company. If independent samples of size n1=10 from line-1 has a standard deviation of S1=0.035 mil and sample size of n2=12 from line-2 has a standard deviation of s2=0.062 mil, estimate the confidence intervals for the ratio of standard deviation of line-1 to line-2 (s12/s22)

Calculate the Mean, Median, Standard Deviation, Coefficient of Variation and 95% population mean confidence intervals for...

Calculate the Mean, Median, Standard Deviation, Coefficient of Variation and 95% population mean confidence intervals for property prices of Houses based on the following grouping:  Proximity of the property to CBD Note: Calculate above statistics for both “Up to 5KM” and “Between 5KM and 10KM”  Number of bedrooms Note: Calculate above statistics for “One bedroom”, “Two bedrooms” and “Three bedrooms or more”  Number of bathrooms Note: Calculate above statistics for “One bathroom”, “Two bathrooms”, “Three bathrooms or...

Find the mean, standard deviation, 80%, 95%, and 99% confidence intervals, and margin of error for...

Find the mean, standard deviation, 80%, 95%, and 99% confidence intervals, and margin of error for those intervals. Show all work. $32,096 $29,716 $29,227 $27,209 $22,794 $19,306 $19,238 $19,164 18,994 $18,329 $17,978 $17,626 $16,823 $16,709 $15,967 $15,921 $15,908 $15,905 $15,638 $15,629 $14,414 $14,229 $14,137 $14,051 $13,907 $13,776 $13,281 $12,739 $12,300 $11,994 $11,262 $11,112 $10,984 $10,824 $10,823 $10,448 $10,081 $9,883 $9,668 $9,663 $9,337 $8,855 $8,741 $8,596 $8,385 $7,204 $7,072 $6,503 $5,653 $4,602

mean 94.6129 n= 31 standard deviation is 45.0612 find the 95% and 99% confidence intervals of...

mean 94.6129 n= 31 standard deviation is 45.0612 find the 95% and 99% confidence intervals of the standard devaition find the 95% and 99% confidence interval for population mean data set 10 19 35 39 41 56 67 67 69 73 75 78 81 82 83 83 84 91 92 94 123 125 137 138 140 142 150 152 161 163 183

1. Develop 90 %, 95 %, and 99% confidence intervals for population mean (µ) when sample...

1. Develop 90 %, 95 %, and 99% confidence intervals for population mean (µ) when sample mean is 10 with the sample size of 100. Population standard deviation is known to be 5. 2. Suppose that sample size changes to 144 and 225. Develop three confidence intervals again. What happens to the margin of error when sample size increases? 3. A simple random sample of 400 individuals provides 100 yes responses. Compute the 90%, 95%, and 99% confidence interval for...

1. Develop 90 %, 95 %, and 99% confidence intervals for population mean (µ) when sample...

1) Construct 90%, 95%, and 99% confidence intervals for the population mean of total daily sales....

1) Construct 90%, 95%, and 99% confidence intervals for the population mean of total daily sales. 2) Run a hypothesis test on the population mean for total daily sales. Use a hypothesized value of $1600 and test at levels of significance of 0.01, 0.05, and 0.10. Use both the critical value and p-value approaches when testing at each level of significance. TABLE 4:TOTAL DAILY SALES $1,800 $975 $1,814 $1,421 $1,335 $1,273 $1,592 $1,305 $1,103 $1,105 $1,438 $1,219 $1,661 $1,692 $1,709...

Give and interpret the 95% confidence intervals for males and a second 95% confidence interval for...

Give and interpret the 95% confidence intervals for males and a second 95% confidence interval for females on the SLEEP variable. Which is wider and why? Known values for Male and Female: Males: Sample Size = 17; Sample Mean = 7.765; Standard Deviation = 1.855 Females: Sample Size = 18; Sample Mean = 7.667; Standard Deviation = 1.879 Using t-distribution considering sample sizes (Male/Female count) are less than 30

Using the data down and interpret 95% confidence intervals for the mean age of an American...

Using the data down and interpret 95% confidence intervals for the mean age of an American truck driver. This data represents a random sample of drivers in America. There are about 3.5 million truck drivers in the USA. Find:1- Sample Standard Deviation. 2- Sample Mean. 3- Sample size. 4- Standard error of the mean. 5-T-value. 6- Interval half-width. 7-Interval lower limit. 8- Interval upper limit . Please use this data. Truck Drivers Employee Gender Age Total education years 1 M 30...

Find the range for the population mean value with 95% and 65% confidence intervals for each...

Find the range for the population mean value with 95% and 65% confidence intervals for each set of data. mean1=3.611, Standard Deviation1=0.02c m, n=24, Mean2=3.632, Standard Deviation2=0.06 cm, n2=17

Subjects