A 5.691 g sample of one such additive containing only lead, carbon, and hydrogen was burned...

A 5.691 g sample of one such additive containing only lead, carbon, and hydrogen was burned in an oxygen‑rich environment. The products of the combustion were 6.194 g CO2(g) and 3.169 g H2O(g) .Determine the empirical formula of the gasoline additive.

empirical formula:[ CHPb ]

Expert Solution

C % = 12*wt of CO2*100/44*wt of organic compound

= 12*6.194*100/44*5.691 = 29.7%

H% = 2*wt of H2O*100/18*wt of organic compound

= 2*3.169*100/18*5.691 = 6.18%

Pb% = 100-(C%+ H%)

= 100-(29.7+6.18) = 64.12%

Element % A.Wt Relative number simple ratio

C 29.7 12 29.7/12 = 2.475 2.475/0.31 = 8

H 6.18 1 6.18/1 = 6.18 6.18/0.31 = 20

Pb 64.12 208 64.12/208 = 0.31 0.31/0.31 = 1

The empirical formula = C8H20Pb

queen_honey_blossom answered 1 year ago

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