Question :01 Part A The initial conditions of a d.c. motor are: K’ = 3:0Vs V1...

Question :01 Part A

The initial conditions of a d.c. motor are:
K’ = 3:0Vs
V1 = 24:0V
Td = 18Nm
Ra = 2 ohm
For a 50 percent increase in the armature voltage, calculate the percentage Change in the no-load speed. Assume that the load torque is unchanged.

Is the increase in speed proportional to increase in armature voltage give reson for your answer.
speed.

Part B:

A 50 V, d.c. shunt motor drives a constant-torque load at a speed of 1200 rpm. The armature and field
resistances are 2 ohm and 100 ohm, respectively. The motor draws a line current of 15 A at the given
load.
(a) Calculate the change in voltage to open the motor to holding position(holding position mean "Yes stopping motor electrically"). And plot the change in
speed with bith the voltages.
(b) Calculate the resistance that should be added to the armature circuit to reduce the speed by 50
percent.
(c) Calculate the resistance that must be added to the armature circuit to open the motor at the
holding condition.
(d) Plot all the resistance for change in speed.

Solutions

Expert Solution

Manojponduru answered 7 months ago

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