In: Operations Management
The Carbondale Hospital is considering the purchase of a new ambulance. The decision will rest partly on the anticipated mileage to be driven next year. The miles driven during the past 5 years are as follows:
Year |
1 |
2 |
3 |
4 |
5 |
Mileage |
3,000 |
4,050 |
3,400 |
3,750 |
3,700 |
a) Using a 2-year moving average, the forecast for year 6 =
miles (round your response to the nearest whole number).
b) If a 2-year moving average is used to make the forecast, the MAD based on this =
miles (round your response to one decimal place). (Hint: You will have only 3 years of matched data.)
c) The forecast for year 6 using a weighted 2-year moving average with weights of 0.45 and 0.55 (the weight of 0.55 is for the most recent period) =
miles (round your response to the nearest whole number).
The MAD for the forecast developed using a weighted 2-year moving average with weights of 0.45 and 0.55 =
miles (round your response to one decimal place). (Hint: You will have only 3 years of matched data.)
d) Using exponential smoothing with α = 0.30 and the forecast for year 1 being 3,050, the forecast for year 6 =
miles (round your response to the nearest whole number).
Answer a)
Year |
Mileage |
Forecast |
1 |
3,000 |
|
2 |
4,050 |
|
3 |
3,400 |
|
4 |
3,750 |
|
5 |
3,700 |
|
6 |
3,725 |
Forecast of year 6 = (Mileage for Year 4 + Mileage for Year 5)/2 = (3750+3700)/2 = 3725 miles
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Answer b)
Year |
Mileage |
Forecast |
Errors |
Absolute |
T |
At |
Ft |
et = At-Ft |
|et| |
1 |
3,000 |
|||
2 |
4,050 |
|||
3 |
3,400 |
3,525 |
-125 |
125 |
4 |
3,750 |
3,725 |
25 |
25 |
5 |
3,700 |
3,575 |
125 |
125 |
6 |
3,725 |
|||
MAD |
91.7 |
MAD = Average of Absolute Errors for Year 3, 4 and 5 = (125+25+125)/3 = 91.7
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Answer c)
Forecast for year 6:
Year |
Mileage |
Forecast |
1 |
3,000 |
|
2 |
4,050 |
|
3 |
3,400 |
|
4 |
3,750 |
|
5 |
3,700 |
|
6 |
3723 |
Forecast for year 6 = (3750*0.45) + (3700*0.55) = 3723 miles
MAD calculation:
Year |
Mileage |
Forecast |
Errors |
Absolute |
t |
At |
Ft |
et = At-Ft |
|et| |
1 |
3,000 |
|||
2 |
4,050 |
|||
3 |
3,400 |
3578 |
-178 |
178 |
4 |
3,750 |
3693 |
57 |
57 |
5 |
3,700 |
3593 |
107 |
107 |
6 |
3723 |
|||
MAD |
114.0 |
MAD = Average of Absolute Errors for Year 3, 4 and 5 = (178+57+107)/3 = 114.0
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Answer d)
Exponential smoothing Forecast formula:
F(t+1)= Ft + α(At-Ft)
Where,
α = Smoothing constant =0.3
Ft = Forecast for immediate previous period
At = Actual Demand for immediate previous period
F(t+1) = Single exponential smoothing forecast for current period
Based on the formula, following is the calculated forecast:
Year |
Mileage (At) |
Forecast |
1 |
3,000 |
3050 |
2 |
4,050 |
3035.00 |
3 |
3,400 |
3339.50 |
4 |
3,750 |
3357.65 |
5 |
3,700 |
3475.36 |
6 |
3543 |
|
Smoothing constant = α = |
0.30 |
Forecast for Year 6 = 3475.36 + 0.30*(3700-3475.36) = 3543 miles
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