Question

In: Operations Management

The Carbondale Hospital is considering the purchase of a new ambulance. The decision will rest partly...

The Carbondale Hospital is considering the purchase of a new ambulance. The decision will rest partly on the anticipated mileage to be driven next year. The miles driven during the past 5 years are as​ follows:

                                                                                                                 

Year

1

2

3

4

5

Mileage

3,000

4,050

3,400

3,750

3,700

​a) Using a​ 2-year moving​ average, the forecast for year 6​ =

miles ​(round your response to the nearest whole​ number).

​b) If a​ 2-year moving average is used to make the​ forecast, the MAD based on this​ =

miles ​(round your response to one decimal​ place). ​ (Hint: You will have only 3 years of matched​ data.)

​c) The forecast for year 6 using a weighted​ 2-year moving average with weights of 0.45 and 0.55 ​(the weight of 0.55 is for the most recent​ period) =

miles ​(round your response to the nearest whole​ number).

The MAD for the forecast developed using a weighted​ 2-year moving average with weights of 0.45 and 0.55 ​=

miles ​(round your response to one decimal​ place).  ​(Hint: You will have only 3 years of matched​ data.)

​d) Using exponential smoothing with α = 0.30 and the forecast for year 1 being 3,050​, the forecast for year 6​ =

miles ​(round your response to the nearest whole​ number).

Solutions

Expert Solution

Answer a)

Year

Mileage

Forecast

1

3,000

2

4,050

3

3,400

4

3,750

5

3,700

6

3,725

Forecast of year 6 = (Mileage for Year 4 + Mileage for Year 5)/2 = (3750+3700)/2 = 3725 miles

-----------------------------------------------------------------

Answer b)

Year

Mileage

Forecast

Errors

Absolute
Errors

T

At

Ft

et = At-Ft

|et|

1

3,000

2

4,050

3

3,400

3,525

-125

125

4

3,750

3,725

25

25

5

3,700

3,575

125

125

6

3,725

MAD

91.7

MAD = Average of Absolute Errors for Year 3, 4 and 5 = (125+25+125)/3 = 91.7

-----------------------------------------------------------------

Answer c)

Forecast for year 6:

Year

Mileage

Forecast

1

3,000

2

4,050

3

3,400

4

3,750

5

3,700

6

3723

Forecast for year 6 = (3750*0.45) + (3700*0.55) = 3723 miles

MAD calculation:

Year

Mileage

Forecast

Errors

Absolute
Errors

t

At

Ft

et = At-Ft

|et|

1

3,000

2

4,050

3

3,400

3578

-178

178

4

3,750

3693

57

57

5

3,700

3593

107

107

6

3723

MAD

114.0

MAD = Average of Absolute Errors for Year 3, 4 and 5 = (178+57+107)/3 = 114.0

-----------------------------------------------------------------

Answer d)

Exponential smoothing Forecast formula:   

F(t+1)= Ft + α(At-Ft)

Where,

α = Smoothing constant =0.3     

Ft = Forecast for immediate previous period      

At = Actual Demand for immediate previous period        

F(t+1) = Single exponential smoothing forecast for current period           

Based on the formula, following is the calculated forecast:

Year

Mileage (At)

Forecast
(Ft)

1

3,000

3050

2

4,050

3035.00

3

3,400

3339.50

4

3,750

3357.65

5

3,700

3475.36

6

3543

Smoothing constant = α =

0.30

Forecast for Year 6 = 3475.36 + 0.30*(3700-3475.36) = 3543 miles

------------------------------------------------------------------------

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