Question

Write a complete program (possible to compile) that:
1) declares two local integers x and y
2) defines a global structure containing two pointers (xptr,yptr) and an integer (z)
3) Declares a variable (mst) by the type of previous structure
4) requests the values of x and y from the user using only one scanf statement
5) sets the first pointer in the struct to point to x
6) sets the second pointer in the struct to point to y
7) uses the structure to print out the values in x and y (do not print x and y values directly)

8) Declare a variable (mstptr) that is a pointer to the structure and make it point to the structure you already declared (mst)

9) Using the pointer to the structure set the integer z in thestructure to the number 5.

10) Using the pointer to the structure display the value of the integer and the values pointed to by the two pointers (must use -> operator)

C++ Coding Please and if you could put comments down that would be amazing!

Answer 1

Please find the answer below.
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#include<iostream>
using namespace std;

struct Point{
   int *xptr;
   int *yptr;
   int z;
};

int main()
{
   //declare x and y
   int x,y;

   //object of structure
   struct Point mst;

   //ask for the input
   printf("Enter value of x and y : ");
   scanf("%d%d",&x,&y);

   //set x and y to pointer
   mst.xptr = &x;
   mst.yptr = &y;

   //print x and y using mst pointer
   printf("Printing the value using mst pointer\n");
   printf(" x = %d\n",*mst.xptr);
   printf(" y = %d\n",*mst.yptr);

   //define pointer to structure
   struct Point *mstptr=&mst;

   //set value to z
   mstptr->z=5;
   printf("\nPrinting the value using structure pointer\n");
   //print x and y and z using structure point
   printf(" x = %d\n",*mstptr->xptr);
   printf(" y = %d\n",*mstptr->yptr);
   printf(" z = %d\n",mstptr->z);
   return 0;

}