What is the percentage ionization of 0.10 M HC2H3O2?

What is the percentage ionization of 0.10 M HC2H3O2?

Expert Solution

Let α be the dissociation of the weak acid
HA <---> H ⁺ + A^-

initial conc. c 0 0

change -cα +cα +cα

Equb. conc. c(1-α) cα cα

Dissociation constant , K_a = cα x cα / ( c(1-α)

= c α² / (1-α)

In the case of weak acids α is very small so 1-α is taken as 1

So K_a = cα²

==> α = √ ( K_a / c )

Given K_a = 1.8x10^-5

c = concentration = 0.10 M

Plug the values we get α = 0.0134

∴ % dissociation = 0.0134 x 100 = 1.34

queen_honey_blossom answered 2 years ago

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