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What volume (in milliliters) of 0.200 M NaOH should be added to a 0.125 L solution...

What volume (in milliliters) of 0.200 M NaOH should be added to a 0.125 L solution of 0.0280 M glycine hydrochloride (pKa1 = 2.350, pKa2 = 9.778) to adjust the pH to 2.73?

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Expert Solution

pKa1 = 2.350

pKa2 = 9.778

glycine moles = 0.125 x 0.0280

                       = 0.0035 mol

H2A+    +   OH-    ---------------> HA

0.0035       x                                -

0.0035-x            -                                x

pH = pKa + log [salt / acid]

2.73 = 2.350 + log [x / 0.0035-x]

[x / 0.0035-x] = 2.3988

x = 8.396 x 10^-3 - 2.3988 x

x = 2.47 x 10^-3

volume of NaOH = moles / concentration

                          = 0.00247 / 0.200

volume of NaOH = 0.0123 L

volume of NaOH = 12.4 mL

queen_honey_blossom answered 2 years ago
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