A single-effect evaporator is concentrating a feed of 9072 g/h of a 10 wt% solution of...

A single-effect evaporator is concentrating a feed of 9072 g/h of a 10 wt% solution of NaOH in water to a product of 50% solids. The pressure of the saturated steam used is 42 kPa (gage) and the pressure in the vapor space of the evaporator is 20 kPa (abs). The overall heat-transfer coefficient is 1988 W/m2*K. a) calculate the steam use, steam economy and area if the feed temperature at 288.8 k (15.6 c) b) predict the new product composition if the feed rate is reduced to 4536 kg/h

Expert Solution

NOTE: 1. DEAR STUDENT IF YOU WANT SOLUTION WITH ENTHAPY DATA FROM STEAM TABLE, KINDLY INFORM ME & I SHALL REUPLOAD THE SOLUTION. HOWEVER, RESULT WILL NOT VARY BY MUCH.

DEAR STUDENT FOR PARTA, FEED FLOW RATE IS MENTIONED AS 9072G/HR.& SOLUTION IS PROVIDED FOR PART A CONSIDERING THE SAME. IF UNIT IS KG/HR, THEN KINDLY INFORM ME & I SHALL MAKE MINOR ADJUSTMENTS REQUIRED IN SOLUTION. IN THAT CASE, AREA & STEAM CONSUMPTION ANSWER SHALL DIFFER.

IN PART B, REDUCED FLOW RATE IS HIGHER THAN ORIGINAL FLOW RATE HENCE SAME HAS BEEN CONSIDERED IN GRAM /HR.

IN CASE OF ANY DOUBT, FEEL FREE TO ASK & I SHALL TRY MY BEST TO RESOLVE YOUR QUERY. THANK YOU.

Amanda K answered 2 years ago

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