In: Civil Engineering
The Dept. of Transportation is comparing two alternative pavement designs with the following cost characteristics. Determine the least expensive alternative with a method of your choice. i=5% per year compounded annually.
Construction Cost at year 0
Maintenance Cost from years 1-20
| Year | A | B |
|---|---|---|
| 0 | $450,000 | $700,000 |
| 1 | ||
| 2 | ||
| 3 | $40,000 | |
| 4 | ||
| 5 | $50,000 | |
| 6 | $40,000 | |
| 7 | ||
| 8 | ||
| 9 | $40,000 | |
| 10 | $50,000 | |
| 11 | ||
| 12 | End of Service | |
| 13 | ||
| 14 | ||
| 15 | $500,000 | |
| 16 | ||
| 17 | ||
| 18 | ||
| 19 | ||
| 20 | End of Service |

equivalent
uniform annual worth method is best suitable for the alternarives
having different lifespan.
the alternative having lesser equivalent uniform annual cost is least expansive.
in the above problem
alternative A has equivalent uniform annual cost
alternative B has equivalent uniform annual cost
hence alternative A is least expansive.
**** there should be a small correction in the cost of
alternative B at 15th yr (it should be
in place of
)
solution is done by
taking