In: Chemistry
if actual amount of alum obtained from 2.535 grams of aluminum sulfate is 3.509g. what is the percent yield of alum?
K2SO4 + Al2(SO4)3. + 24H2O --------------------> K2SO4 Al2(SO4)3.24H2O
342.1 g 948.77 g
2.535 g ?
alum thereotical mass = 948.77 x 2.535 / 342.1
= 7.030 g
percent yield of alum = actual x 100 / hereotical
= 3.509 x 100 / 7.030
= 49.9 %