. The reaction of 2O3(g) → 3O2(g) has the experimental rate: rate = k[O3]2 [O2]—1. The...

. The reaction of 2O3(g) → 3O2(g) has the experimental rate: rate = k[O3]2 [O2]—1. The following mechanism has been proposed: 1. O3 O2 + O fast, equilibrium 2. O + O3 → 2 O2 slow (A) Identify any intermediates. (B) What is the rate law predicted by this mechanism? (C) Is the rate law predicted by the mechanism consistent with the experimental rate law? (D) How would adding a catalyst effect this reaction?

Expert Solution

A] Intermediates = [O]

D] Adding catalyst will not affect the rate equation but will help in attaining equilibrium faster by reducing the activation energy. The reaction mechanism is given below:

Amanda K answered 1 year ago

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