In: Math
The American Society of PeriAnesthesia Nurses (ASPAN; www.aspan.org) is a national organization serving nurses practicing in ambulatory surgery, preanesthesia, and postanesthesia care. The organization's membership is listed below.
State/Region | Membership | ||
Alabama | 138 | ||
Arizona | 489 | ||
Maryland, Delaware, DC | 551 | ||
Connecticut | 273 | ||
Florida | 522 | ||
Georgia | 461 | ||
Hawaii | 87 | ||
Maine | 145 | ||
Minnesota, Dakotas | 385 | ||
Missouri, Kansas | 194 | ||
Mississippi | 87 | ||
Nebraska | 73 | ||
North Carolina | 387 | ||
Nevada | 64 | ||
New Jersey, Bermuda | 531 | ||
Alaska, Idaho, Montana,Oregon, Washington | 640 | ||
New York | 966 | ||
Ohio | 888 | ||
Oklahoma | 164 | ||
Arkansas | 93 | ||
Illinois | 498 | ||
Indiana | 362 | ||
Iowa | 128 | ||
Kentucky | 205 | ||
Louisiana | 158 | ||
Michigan | 467 | ||
Massachusetts | 341 | ||
California | 1,098 | ||
New Mexico | 37 | ||
Pennsylvania | 371 | ||
Rhode Island | 65 | ||
Colorado | 247 | ||
South Carolina | 284 | ||
Texas | 1,108 | ||
Tennessee | 219 | ||
Utah | 87 | ||
Virginia | 353 | ||
Vermont, New Hampshire | 134 | ||
Wisconsin | 257 | ||
West Virginia | 60 |
find standard deviation, first and third quartile, and the limits for the outliers
To find Standard deviation we need to find mean first
Create the following table.
data | data-mean | (data - mean)2 |
138 | -202.425 | 40975.880625 |
489 | 148.575 | 22074.530625 |
551 | 210.575 | 44341.830625 |
273 | -67.425 | 4546.130625 |
522 | 181.575 | 32969.480625 |
461 | 120.575 | 14538.330625 |
87 | -253.425 | 64224.230625 |
145 | -195.425 | 38190.930625 |
385 | 44.575 | 1986.930625 |
194 | -146.425 | 21440.280625 |
87 | -253.425 | 64224.230625 |
73 | -267.425 | 71516.130625 |
387 | 46.575 | 2169.230625 |
64 | -276.425 | 76410.780625 |
531 | 190.575 | 36318.830625 |
640 | 299.575 | 89745.180625 |
966 | 625.575 | 391344.080625 |
888 | 547.575 | 299838.380625 |
164 | -176.425 | 31125.780625 |
93 | -247.425 | 61219.130625 |
498 | 157.575 | 24829.880625 |
362 | 21.575 | 465.480625 |
128 | -212.425 | 45124.380625 |
205 | -135.425 | 18339.930625 |
158 | -182.425 | 33278.880625 |
467 | 126.575 | 16021.230625 |
341 | 0.57499999999999 | 0.33062499999999 |
1098 | 757.575 | 573919.880625 |
37 | -303.425 | 92066.730625 |
371 | 30.575 | 934.830625 |
65 | -275.425 | 75858.930625 |
247 | -93.425 | 8728.230625 |
284 | -56.425 | 3183.780625 |
1108 | 767.575 | 589171.380625 |
219 | -121.425 | 14744.030625 |
87 | -253.425 | 64224.230625 |
353 | 12.575 | 158.130625 |
134 | -206.425 | 42611.280625 |
257 | -83.425 | 6959.730625 |
60 | -280.425 | 78638.180625 |
Find the sum of numbers in the last column to get.
So standard deviation =
The first quartile (or lower quartile or 25th percentile) is the median of the bottom half of the numbers. So, to find the first quartile, we need to place the numbers in value order and find the bottom half.
37 60 64 65 73 87 87 87 93 128 134 138 145 158 164 194 205 219 247 257 273 284 341 353 362 371 385 387 461 467 489 498 522 531 551 640 888 966 1098 1108
So, the bottom half is
37 60 64 65 73 87 87 87 93 128 134 138 145 158 164 194 205 219 247 257
The median of these numbers is 131.
The third quartile (or upper quartile or 75th percentile) is the median of the upper half of the numbers. So, to find the third quartile, we need to place the numbers in value order and find the upper half.
37 60 64 65 73 87 87 87 93 128 134 138 145 158 164 194 205 219 247 257 273 284 341 353 362 371 385 387 461 467 489 498 522 531 551 640 888 966 1098 1108
So, the upper half is
273 284 341 353 362 371 385 387 461 467 489 498 522 531 551 640 888 966 1098 1108
The median of these numbers is 478.
The interquartile range is the difference between the third and first quartiles.
The third quartile is 478.
The first quartile is 131.
The interquartile range = 478 - 131 = 347.
Limit for the outliers are and