Question

The American Society of PeriAnesthesia Nurses (ASPAN; www.aspan.org) is a national organization serving nurses practicing in ambulatory surgery, preanesthesia, and postanesthesia care. The organization consists of the 40 components listed below. State/Region Membership Alabama 107 Arizona 432 Maryland, Delaware, DC 608 Connecticut 302 Florida 525 Georgia 385 Hawaii 72 Illinois 415 Indiana 212 Iowa 97 Kentucky 178 Louisiana 187 Michigan 497 Massachusetts 453 Maine 70 Minnesota, Dakotas 200 Missouri, Kansas 352 Mississippi 127 Nebraska 132 North Carolina 527 Nevada 101 New Jersey, Bermuda 707 Alaska, Idaho, Montana, Oregon, Washington 708 New York 912 Ohio 908 Oklahoma 199 Arkansas 64 California 992 New Mexico 100 Pennsylvania 673 Rhode Island 70 Colorado 498 South Carolina 279 Texas 888 Tennessee 197 Utah 77 Virginia 254 Vermont, New Hampshire 114 Wisconsin 402 West Virginia 38
Find the mean, median, and standard deviation of the number of members per component. (Round your answers to 2 decimal places.) b-1.
Find the coefficient of skewness, using the software method. (Round your answer to 2 decimal places.) b-2.
What do you conclude about the shape of the distribution of component size?
Mild positive skewness Mild negative skewness
Determine the first and third quartiles. Do not use the method described by Excel. (Round your answers to 2 decimal places.) d-1
What are the limits for outliers? (Round your answers to the nearest whole number. Negative amounts should be indicated by a minus sign.) d-2.

Are there any outliers? Zero One Three Four Two

Answer 1

Population size, N =40

Sum, =14059

Mean, =14059/40 =351.48

Median, M= the middle most value after arranging the data in an ascending order(here, average of two middle most values) =266.50

Standard deviation, =270.87

b-1:

Coefficient of skewness, Sk = =0.80

b-2:

The shape of the distribution is Mild positive skewness because Sk = +0.80

First quartile, Q1 =108.75

Third quartile, Q3 =518.25

d-1:

Outliers are the values that are below Q1 - 1.5(IQR) or above Q3 + 1.5(IQR).

1.5(IQR) =1.5(Q3 - Q1) =1.5(518.25 - 108.75)=614.25

Lower limit =Q1 - 614.25 =108.75 - 614.25 = -506

Upper limit =Q3 + 614.25 =518.25 + 614.25 =1133

d-2:

"Zero" outliers is correct option.

There are no outliers in the data as no value is less than -506 or greater than 1133.