Question

The American Society of PeriAnesthesia Nurses (ASPAN; www.aspan.org) is a national organization serving nurses practicing in ambulatory surgery, preanesthesia, and postanesthesia care. The organization's membership is listed below.

State/Region	Membership
Alabama		128
Arizona		388
Maryland, Delaware, DC		549
Connecticut		183
Florida		659
Georgia		533
Hawaii		69
Maine		110
Minnesota, Dakotas		212
Missouri, Kansas		216
Mississippi		134
Nebraska		112
North Carolina		387
Nevada		153
New Jersey, Bermuda		616
Alaska, Idaho, Montana,Oregon, Washington		579
New York		1,077
Ohio		767
Oklahoma		144
Arkansas		89
Illinois		644
Indiana		356
Iowa		106
Kentucky		172
Louisiana		302
Michigan		493
Massachusetts		442
California		1,186
New Mexico		93
Pennsylvania		500
Rhode Island		70
Colorado		484
South Carolina		316
Texas		787
Tennessee		199
Utah		44
Virginia		538
Vermont, New Hampshire		114
Wisconsin		373
West Virginia		47

1. Find the mean, median, and standard deviation of the number of members per component. (Round your answers to 2 decimal places.)
2. Find the coefficient of skewness, using the software method. (Round your answer to 2 decimal places.)
3. Determine the first and third quartiles. Do not use the method described by Excel. (Round your answers to 2 decimal places.)

4. What are the limits for outliers? (Round your answers to the nearest whole number. Negative amounts should be indicated by a minus sign.)

Answer 1

a. Since these data is for whole organization, treat this data as population. Consider the following table:

	128	-231.275	53488.125625
	388	28.725	825.125625
	549	189.725	35995.575625
	183	-176.275	31072.875625
	659	299.725	89835.075625
	533	173.725	30180.375625
	69	-290.275	84259.575625
	110	-249.275	62138.025625
	212	-147.275	21689.925625
	216	-143.275	20527.725625
	134	-225.275	50748.825625
	112	-247.275	61144.925625
	387	27.725	768.675625
	153	-206.275	42549.375625
	616	256.725	65907.725625
	579	219.725	48279.075625
	1077	717.725	515129.175625
	767	407.725	166239.675625
	144	-215.275	46343.325625
	89	-270.275	73048.575625
	644	284.725	81068.325625
	356	-3.275	10.725625
	106	-253.275	64148.225625
	172	-187.275	35071.925625
	302	-57.275	3280.425625
	493	133.725	17882.375625
	442	82.725	6843.425625
	1186	826.725	683474.225625
	93	-266.275	70902.375625
	500	140.725	19803.525625
	70	-289.275	83680.025625
	484	124.725	15556.325625
	316	-43.275	1872.725625
	787	427.725	182948.675625
	199	-160.275	25688.075625
	44	-315.275	99398.325625
	538	178.725	31942.625625
	114	-245.275	60159.825625
	373	13.725	188.375625
	47	-312.275	97515.675625
SUM	14371		3081607.975000

The mean is:

For median, first arrange data in ascending order and find average of two middle values.

44	47	69	70	89	93	106	110	112	114
128	134	144	153	172	183	199	212	216	302
316	356	373	387	388	442	484	493	500	533
538	549	579	616	644	659	767	787	1077	1186

Here two middle values are 302 and 316. Therefore, median is:

The standard deviation is:

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b. The coefficient of skewness is:

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c. For quartiles, first arrange data in ascending order (as we did in median) and split data in two parts. The median of lower half of the data is first quartile and median of other half of the data is third quartile.

44	47	69	70	89	93	106	110	112	114
128	134	144	153	172	183	199	212	216	302

Here two middle values are 114 and 128. Therefore, first quartile is:

316	356	373	387	388	442	484	493	500	533
538	549	579	616	644	659	767	787	1077	1186

Here two middle values are 533 and 538. Therefore, third quartile is:

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d. The interquartile range is: