In: Statistics and Probability
student GPA and monthly salary after graduation in $. You collect data from 6 students.
Student |
Years of Work Experience |
GPA |
Monthly Salary ($) |
1 |
3 |
2.6 |
3300 |
2 |
0 |
3.4 |
3600 |
3 |
4 |
3.6 |
4000 |
4 |
1 |
3.2 |
3500 |
5 |
2 |
3.5 |
3900 |
6 |
5 |
2.9 |
3600 |
Following are the regression results for the data using Excel. In this problem, you will be interpreting the regression results.
Please answer the following questions based on this table
5) Which variables have a statistically significant relationship with the dependent variable at the 1% level?(Use three decimals on p value)
6) What is the 95% confidence interval estimate for the coefficient of GPA?
7) What is the 90% confidence interval estimate for the coefficient of Years of work experience?
The regression output is as follows
Question (5)
The dependent variable here is Monthly Salary ($) and the independent variables are Years of Work Experience and GPA
If the p-value of independent variable is less than significance level 0.01, then we can say that that the independent variable is statistically significant
Here the p-value of Work of years experience indpendent variable is 0.018714 which is less than significance level of 0.01, hence the independent variable Years of Work Experience has a statistically significant relationship with Monthly Salary ($)
Here the p-value of GPA indpendent variable is 0.002456 which is less than significance level of 0.01, hence the independent variable GPA has a statistically significant relationship with Monthly Salary ($)
Question (6)
The 95% confidence interval estimate for the coefficient of GPA
95% CI for GPA = 683.1346 t-value * 71.7393
Here 683.1346 is the coefficient of GPA and 71.7393 is the standard error of GPA
degrees of freedom (df) = n -2
= 6 - 2
= 4
So the t-value at 95% confidence level and degrees of freedom 4 from the below attached table = 2.776
You can find the confidence level at the bottom of the image
So 95% CI for GPA = 683.1346 2.776 * 71.7393
= 683.1346 199.1483
So 95% CI for GPA = (483.9863, 882.2929)
Question (7)
The 90% confidence interval estimate for the coefficient of Years of Work Experience
90% CI for Years of Work Experiecne = 68.6542 t-value * 14.7521
Here 68.6542 is the coefficient of Years of Work experience and 14.7521 is the standard error of Years of Work Experience
degrees of freedom (df) = n -2
= 6 - 2
= 4
So the t-value at 90% confidence level and degrees of freedom 4 from the below attached table = 2.132
You can find the confidence level at the bottom of the image
So 90% CI for Years of Work Expericne = 68.6542 2.132 * 14.7521
= 68.6542 31.4515
So 90% CI for Years of Work Experience = (37.2027, 100.106)