Question

if 92.8 grams of sodium nitrite are dissolved in 2.3L of water, the resulting solution has a molarity of

Answer 1

Answer – We are given, mass of sodium nitrite = 92.8 g , volume = 2.3 L

First we need to convert the given mass of sodium nitrite to moles

Moles of sodium nitrite , NaNO₂ = 92.8 g / 68.9953 g.mol^-1

                                                     = 1.345 moles

We are given volume of water and we know density of water is 1.0g/mL

Means, 2.3 L = 2.3 kg of water

We know formula for calculating the molality

Molality = moles of solute / kg of solvent

              = 1.345 moles / 2.3 kg

              = 0.58 m

So, the resulting solution has a molarity of 0.58 m