In: Math
Finish | Men | Women |
1 | 66.91 | 110.64 |
2 | 67.88 | 112.83 |
3 | 68.13 | 113.26 |
4 | 68.46 | 113.54 |
5 | 72.48 | 115.99 |
6 | 88.79 | 119.94 |
7 | 98.06 | 122.86 |
8 | 100.13 | 123.69 |
9 | 102.13 | 124.09 |
10 | 109.79 | 124.23 |
11 | 110.66 | 125.49 |
12 | 111.84 | 127.39 |
13 | 114.51 | 131.13 |
14 | 115.13 | 131.48 |
15 | 122.56 | 132.33 |
16 | 129.59 | 133.28 |
17 | 130.01 | 133.64 |
18 | 132.51 | 134.81 |
19 | 133.41 | 135.11 |
20 | 140.24 | 138.18 |
21 | 145.44 | 138.36 |
22 | 150.31 | 139.81 |
23 | 140.61 | |
24 | 148.79 | |
25 | 148.96 | |
26 | 149.11 | |
27 | 149.36 | |
28 | 155.49 | |
29 | 156.44 | |
30 | 190.88 | |
31 | 190.89 |
Compare the firstplace finish times for men and women. If the 53 men and women runners had competed as one group, in what place would winner of women's marathon have finished? Round your answer to 2 decimal places.
The first place runner in the men’s group finished minutes _______aheadbehind of the first place runner in the women’s group.
b. What is the median time for men and women runners? Compare men and women runners based on their median times. Round your answers to 2 decimal places.
Men | Women | |
Median |
Using the median finish times, the men’s group finished minutes _______aheadbehind of the women’s group.
c. Provide a five-number summary for both the men and the women. Round your answers to 2 decimal places.
Men | Women | |
Lowest Time | ||
First Quartile | ||
Median | ||
Third Quartile | ||
Highest Time |
d. Are there outliers in either group?
If data contain outliers enter the value. If there no outliers live answer blank. If there is more than one value, separate your answers with commas (to 2 decimals).
Outliers in the men's group.
Outliers in the women's group.
e. Which of the following box plots accurately displays the data set?
#1 |
Minutes |
#2 |
Minutes |
#3 |
Minutes |
#4 |
Minutes |
_________Box plot #1Box plot #2Box plot #3Box plot #4
Did men or women have the most variation in finish times?
_______MenWomen
a). by combining the men runners and women runners upto the the winner women runner we have:-
Finish | combined data upto the women winner |
1 | 66.91 |
2 | 67.88 |
3 | 68.13 |
4 | 68.46 |
5 | 72.48 |
6 | 88.79 |
7 | 98.06 |
8 | 100.13 |
9 | 102.13 |
10 | 109.79 |
11 | 110.64 |
12 | 110.66 |
the winner of women's marathon would have finished in 11 th place.
The first place runner in the men’s group finished minutes 43.73 ahead behind of the first place runner in the women’s group.
[ time taken by winner of men's marathon = 66.91 minutes
time taken by winner of women's marathon = 110.64 minutes.
so, the men winner has finished:- (110.64-66.91)= 43.73 minutes before the women winner.]
b). for men,
number of observation (n) = 22
this is an even number.so the median will be:-
for women,
number of observation (n) = 31
this is an odd number.so the median will be:-
so the median of men and women be:-
median of men | 111.25 |
median of women | 133.28 |
c).for men,
first quartile()
[ from the given arranged data of men , 5 th observation = 72.48 and 6 th observation =88.79]
third quartile():-
[ from the given arranged data of men , 17 th observation = 130.01 and 18 th observation =132.51]
FOR WOMEN,
first quartile()
[ from the given arranged data of women , 8 th observation = 123.69 ]
third quartile():-
[ from the given arranged data of women , 24 th observation = 148.79]
so, the five number summary be:-
5 number summary | men | women |
min value | 66.91 | 110.64 |
first quartile | 84.71 | 123.69 |
median | 111.25 | 133.28 |
third quartile | 130.63 | 148.79 |
max value | 150.31 | 190.89 |
d).acceptable region= mean 1.5 interquartile range.
for men,
mean = sum of all observation / number of obs
=2378.97/22 = 108.135
IQR = = (130.63-84.71) = 45.92
so, the range be:-
= (108.135 [1.5*45.92] ) = (39.255,177.015)
in MEN group no data is present outside the range, SO NO OUTLIER is present.
for women,
mean = sum of all observation / number of obs
=1212.61 / 31 = 135.89
IQR = = (148.79 - 123.69) = 25.10
so, the range be:-
= (135.89 [1.5*25.10] ) = (98.24 , 173.54)
in WOMEN group two data are present outside the range, SO OUTLIER is present and they are 190.88 , 190.89
e).the boxplot be:-
[steps in minitab:-
graph box plot simple in multiple Y's ok in graph variables select men and women ok.]
men have the most variation in finish times.
[ because the interquartile range of men = 45.92 > interquartile range of women = 25.10
we know that, greater the interquartile range more is the variation. so, MEN has most variation here.]
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