In: Accounting
An industrial engineer is considering two robots for purchase by a fiber optic manufacturing company. Robot X will have a first cost of $125,000, an annual maintenance and operation (M&O) cost of $40,000, and a $60,000 salvage value. Robot Y will have a first cost of $145,000, an annual M&O cost of $33,000, and a $65,000 salvage value. Which should be selected on the basis of an annual worth comparison of 9% per year? Use a 3-year study period.
Interest Rate | 9% | |||||
Robot X Cash Flows | Robot Y Cash Flows | |||||
Year End | Cash Flow | Present Value | Year End | Cash Flow | Present Value | |
0 | 0 | |||||
1 | 1 | |||||
2 | 2 | |||||
3 | 3 | |||||
Total PV | Total PV | |||||
Annual Worth for Robot X | Annual Worth for Robot Y | |||||
-$71,078.56 | -$70,454.38 | |||||
Which model should the company buy? | ||||||
Robot X | ||||
Years | Net cash Outflow | PV Factor9% | Present value | |
0 | Cost of machin | -125000 | 1.000 | -1,25,000.00 |
1 | M&O Cost | -40,000 | 0.91743 | -36,697.25 |
2 | M&O Cost | -40,000 | 0.84168 | -33,667.20 |
3 | M&O Cost | -40,000 | 0.77218 | -30,887.34 |
3 | salvage value | 60,000 | 0.77218 | 46,331.01 |
Total PV of cash outflows | -1,79,921 | |||
Annual Worth for Robot X(PVAF9%,3Year) | 2.531295 | |||
Annual vash out flow | -71,078.56 | |||
Robot Y | ||||
Years | Net cash Outflow | PV Factor9% | Present value | |
0 | Cost of machin | -145000 | 1.000 | -1,45,000.00 |
1 | M&O Cost | -33,000 | 0.91743 | -30,275.23 |
2 | M&O Cost | -33,000 | 0.84168 | -27,775.44 |
3 | M&O Cost | -33,000 | 0.77218 | -25,482.05 |
3 | salvage value | 65,000 | 0.77218 | 50,191.93 |
Total PV of cash outflows | -1,78,341 | |||
Annual Worth for Robot Y(PVAF9%,3Year) | 2.531295 | |||
Annual vash out flow | -70,454.38 | |||
Which model should the company buy? | Robot Y | |||
Because Annual cash outflow is lower than Robot X |